The image of the question is attached below.
Given:
m∠DAC = 20° and m∠BCA = 30°
m∠ABC = 90° and m∠CDA = 90°
To find:
The value of x and y.
Solution:
In right triangle ABC,
m∠BAC = x° + 20°
Sum of the interior angles of a triangle = 180°
m∠BAC +m∠ABC + m∠BCA = 180°
x° + 20° + 90° + 30° = 180°
x° + 140° = 180°
Subtract 140° from both sides.
x° + 140° - 140° = 180° - 140°
x° = 40°
In right triangle ADC,
m∠ACD = y° + 30°
Sum of the interior angles of a triangle = 180°
m∠ACD +m∠CDA + m∠DAC = 180°
y° + 30° + 90° + 20° = 180°
y° + 140° = 180°
Subtract 140° from both sides.
y° + 140° - 140° = 180° - 140°
y° = 40°
The value of x is 40 and y is 40.
Answer:
X= 232÷ 2-40
Step-by-step explanation:
so first you minus the 40 giving you 192. The you do 192 ÷ 2 giving you 96$. So Trey had 96$ saved before mowing lawns.
Answer:
I think your functions are
,
and 
If yes then then the third function which is
.
Step-by-step explanation:
The function
where c is a constant has
Domain : 
Range : ( 0 , ∞ )
The above range is irrespective of the value of c.
I have attached the graph of each of the function, you can look at it for visualization.
- <em>
⇒ </em>This function is same as
so its range is <em>( 0 , ∞ )</em>.
- <em>
⇒ </em>If we double each value of the function
, which has range ( 0 , ∞ ), but still the value of extremes won't change as 0*2=0 and ∞*2=∞. Therefore the range remains as <em>( 0 , ∞ )</em>.
- <em>
</em> ⇒ If we add 2 to each value of the function
, which has range ( 0 , ∞ ), the lower limit will change as 0+2=2 but the upper limit will be same as ∞. Therefore the range will become as <em>( 2 , ∞ )</em>.
Answer:
(0, 33) : Yes
(4.8, 30.5) : Yes
Step-by-step explanation:
height of at least 24 ft : y >= 24
horizontal distance of no more than 10 ft. : 0 <= x <= 10
The vertical height must be at least three times as high as the horizontal distance. No rocket should go higher than 33 ft.:
y >= 3x and y <= 33
So Constraints:
24 <= y <= 33
y >= 3x
0 <= x <= 10
Now check to see if those coordinate points meet all the constraints
(0, 33) : Yes
(4.8, 30.5) : Yes
(9, 26) : No (because 26 is less than (3 * 9) = 27)
(4, 36)
: No (because 36 > 33, must be 24 <= y <= 33)
(2, 22): No (because 22 <24, must be 24 <= y <= 33)
The perimeter of the school crossing sign is 102 inches
length of each side = ?
in the question number of sides is not mentioned, so the answer may vary for the length of each side. if there is 5 sides divide 102 by 5, we get 20.4 answer so in case of 5 sides length of each side is 20.4 inches. if there is 4 sides divide 102 by 4 and we get 25.5 inches answer for the legnth each side.