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Goshia [24]
2 years ago
7

Rena is building a 1:1801:1801, colon, 180 scale model of a real castle. Her model has a rectangular base that is 333 feet wide

and 444 feet long. What is the area of the base of the actual castle in square feet?
Mathematics
1 answer:
liubo4ka [24]2 years ago
7 0

Answer:

388,800 ft^2.

Step-by-step explanation:

Scale = 1 : 180

Actual length, Ls = 180 × 4

= 720 ft

Actual width, Bs = 180 × 3

= 540 ft

Area of a rectangle = Ls × Bs

= 540 × 720

= 388,800 ft^2.

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Calculate the value of x to one decimal place. inches
kakasveta [241]

Use the law of cosines: c^2=a^2+b^2-2ab\cos C

We have:

c=x\\a=3in\\b=7in\\C=54^o

substitute:

\cos54^o\approx0.5878\\\\c^2=3^2+7^2-2\cdot3\cdot7\cdot0.5878\\\\c^2=9+49-24.6876\\\\c^2=33.3129\to c=\sqrt{33.3129}\\\\c\approx5.8

5 0
2 years ago
The equation y=−0.0088x2+0.79x+15 models the speed x (in miles per hour) and average gas mileage y (in miles per gallon) for a v
Neko [114]

we are given

y=-0.0088x^2+0.79x+15

where

y is average gas mileage in miles per gallon

x is speed in miles per hour

we have to find average gas mileage at a speed of 60 miles per hour

so, we have

x=60mph

now, we can plug it and find y

y=-0.0088(60)^2+0.79(60)+15

we get

y=30.72

so,

the best approximate for the average gas mileage at a speed of 60 miles per hour is 30.7 mi/gal...........Answer

6 0
2 years ago
Read 2 more answers
6 points Emily’s family needs to rent a moving truck to move their belongings to a different house. The rental cost for Trucks-A
Alexxx [7]

Answer/Step-by-step explanation:

Equation to represent the daily rental cost for each type of truck can be written as follows:

Daily rental cost for Trucks-A-Lot = 42 + 0.72m

Daily rental cost for Move-in-Truckers = 70 + 0.12m

Where, m = Emily's mileage

To determine the number of miles for which the truck cost the same amount, set both equations equal to each other and solve for m.

42 + 0.72m = 70 + 0.12m

Collect like terms

0.72m - 0.12m = 70 - 42

0.6m = 28

Divide both sides by 0.6

\frac{0.6m}{0.6} = \frac{28}{0.6}

m = 46.7

At approximately 47 miles, both trucks would cost the same amount.

Check:

Daily rental cost for Trucks-A-Lot = 42 + 0.72m

Plug in the value of x = 47

= 42 + 0.72(47) = $75.84 ≈ $76

Daily rental cost for Move-in-Truckers = 70 + 0.12m

Plug in the value of x = 47

= 70 + 0.12(47) = $75.64 ≈ $76

7 0
2 years ago
Sections of prefabricated fencing are each 4 1/3 feet long. how long are 6 1/2 sections placed end to end
zalisa [80]

we know that

4\frac{1}{3}= \frac{(4*3+1)}{3} =\frac{13}{3}

6\frac{1}{2}= \frac{(6*2+1)}{2}=\frac{13}{2}

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Multiply the number of sections by the length of one section

so

\frac{13}{2} *\frac{13}{3} =\frac{169}{6}\ ft

\frac{169}{6}\ ft =28\frac{1}{6}\ ft

therefore

<u>the answer is</u>

28\frac{1}{6} \ ft


6 0
2 years ago
Read 2 more answers
What is the equation of the translated function, g(x), if f(x) = x2?
Eddi Din [679]

All of these would be translated versions of f(x).


A translated version is simply one in which the base equation is used and then moved. Each of these equations are quadratics with a starting term of x^2. All of them move up and down or side to side in some way and direction, but all of them would be translated versions of that graph.

6 0
2 years ago
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