Answer:
3 1/8
Step-by-step explanation:
1. You can add the 2 halves together making 1
2. Then add a 3/4 and one 1/4 together making another 1
3. With the remaining two 1/4s, that makes another half. So at the moment, you have 2 1/2
4. Convert 2 1/2 to eighths. 2 4/8
5. Finally add one 5/8.
So the answer is 3 1/8
Answer:
Step-by-step explanation:
step 1
Find the measure of angle EFD
In this problem I will assume that ABCD is a parallelogram
In a parallelogram opposite angles are congruent and consecutive angles are supplementary
so
--- > given problem
Remember that the sum of the interior angles in any triangle must be equal to 180 degrees
so
In the triangle EFD
substitute the given values
step 2
Find the measure of angle EFB
we know that
---> by supplementary angles
we have
substitute
step 3
Find the value of x
Remember that the sum of the interior angles in any triangle must be equal to 180 degrees
so
In the triangle EBF
we have
substitute
solve for x
Combine like terms

The value of the expression will be 9.
<em><u>Explanation</u></em>
Given expression is : 
First we will simplify both numerator and denominator separately using <u>order of operations</u>. So....

Thus the expression....

Answer:

So then P =11000 is the minimum that the least populated district could have.
Step-by-step explanation:
We have a big total of N = 132000 for the population.
And we know that we divide this population into 11 districts
And we have this info given "no district is to have a population that is more than 10 percent greater than the population of any other district"
Let's assume that P represent our minimum value for a district in the population. The range of possible values for the population of each district would be between P and 1.1 P
The interest on this case is find the minimum value for P and in order to do this we can assume that 1 district present the minimum and the other 10 the maximum value 1.1P in order to find which value of P satisfy this condition, and we have this:


So then P =11000 is the minimum that the least populated district could have.