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sertanlavr [38]

2 years ago

6

Jamaal spent x minutes today practicing his guitar and y minutes today on homework. If the total time he spent on both is 45 min

utes or more, which inequality best represents his practice time?

2 answers:

Free_Kalibri [48]2 years ago

8 0

The answer to the equation is: x + y ≥ 45

Arte-miy333 [17]2 years ago

5 0

<span>In the question "Jamaal spent x minutes today practicing his guitar and y minutes today on homework. If the total time he spent on both is 45 minutes or more, which inequality best represents his practice time?" Since the total time he spent on both is 45 minutes or more, it means that the sum of x and y is greater than or equal to 45. Therefore, the required equation is x + y ≥ 45.</span>

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What is the area of a circle with a radius of 9.4cm

Contact [7]

$A \\ = \pi r ^{2} \\ = 3.14 \times {9.4}^{2} \\ = 277.4504$

Answer : Area = 277.45cm^2

Hope this helps. - M

8 0

2 years ago

Read 2 more answers

NEED HELP ON NUMBER 13 AND 14

Kazeer [188]

Answer:

Question 13: For age groups y=1 and y=1.3 response is 8 microseconds.

Question 14: The club was making a loss between 11.28 and 4.88 years.

Step-by-step explanation:

Question 13:

The age group y for which the response rate R is 8 microseconds is given by the solution of the equation

$8=y^4 +2y^3 - 4y^2 -5y +14.$

We graph this equation and find the solutions to be

$y=1;$ $y=1.302;$ $y=-2;$ $y=-2.302.$

Since only positive solutions for y are valid in the real world we take only those.

Thus only for age groups y=1 and y=1.3 the response is 8 microseconds.

Question 14:

The footbal club is making a loss when $p(t)$

Or

$t^3 -14t^2 +20t +120$

We graph this inequality and find the solutions to be

$t$ and $4.88$

Since in the real world only positive values for t are valid, we take the the second solution to be true.

Thus the club was making a loss in years $4.88$

5 0

2 years ago

A rectangular solid with a square base has a volume of 5832 cubic inches. (Let x represent the length of the sides of the square

Aleks04 [339]

Answer:

a) 18 in x 18 in x 18 in

b) $S = 1944\ in2$

Step-by-step explanation:

a) Let's call 's' the side of the square base and 'h' the height of the solid.

The surface area is given by the equation:

$S = 2s^2 + 4sh$

The volume of the solid is given by the equation:

$V = s^2h = 5832$

From the volume equation, we have that:

$h = 5832/s^2$

Then, using this value of h in the surface area equation, we have:

$S = 2s^2 + 4s(5832/s^2)$

$S = 2s^2 + 23328/s$

To find the side length that gives the minimum surface area, we can find where the derivative of S in relation to s is zero:

$dS/ds = 4s - 23328/s^2 = 0$

$4s = 23328/s^2$

$4s^3 = 23328$

$s^3 = 23328/4 = 5832$

$s = 18\ inches$

The height of the solid is:

$h = 5832/(18)^2 = 18\ inches$

b) The minimum surface area is:

$S = 2(18)^2 + 4(18)(18)$

$S = 1944\ in2$

8 0

2 years ago

All side lengths of ΔJKL equal 2 units. A transformation maps ΔJKL to ΔJ'K'L'. The length of side J'K' is 5 units. Is this a rig

S_A_V [24]

No because at least one segment length is not preserved.
rigid means everything stays the same, but orientation sometimes changes.

5 0

2 years ago

Read 2 more answers

In a box containing 25 cherries, 2 of them are rotten. Susan randomly picks cherries in the box. How many cherries should be pic

bezimeni [28]

Answer:

Susan should pick 6 cherries from box, so the probability of picking the 2 rotten cherries is 1/20

Step-by-step explanation:

assuming that each cherry is equally probable to be chosen , since each cherry is independent from the others and sampling is done without replacement , the random variable X= number of cherries that are rotten from the picked ones follows a hyper geometrical distribution , where

P(X=k)= C(M,k) * C(N-M, n-k) / C(N,n)

where

N= population size = 25

n= number of picks

M = total number of rotten cherries =2

k = number of rotten cherries picked =2

C( ) = combination

then

1/20=C(2,2)*C(25-2,n-2)/C(25,n) = 1 * (23!/(n-2)!*(25-n)! / (25!/(n!*(25-n)!

1/20 = n!/(n-2)! * 1/(24*25)

24*25/20 = n*(n-1)

n²-n-30 =0

n= (1 +√(1+4*1*30))/2 = 12/2= 6

n=6

then Susan should pick 6 cherries from box, so the probability of picking the 2 rotten cherries is 1/20

7 0

2 years ago