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Eddi Din [679]
1 year ago
9

Mason practiced basketball free throws and kept track of the results in the table. He says the experimental probability of makin

g a free throw
is 2/3.

What is Mason’s error?
A.Mason compared the number of free throws missed to the total number of free throws attempted.
B.Mason compared the number of free throws made to the total number of free throws attempted.
C.Mason compared the number of free throws made to the number of free throws missed.
D.Mason compared the number of free throws attempted to the difference between the number made and the number missed.

Mathematics
2 answers:
Gennadij [26K]1 year ago
8 0
Mason compared the number of free throws made to the number of free throws missed. The probability would actually be 2/5 becahse 18+12 is 30, giving you your denominator, then you made 12. So, simplifying 12/30 gives you your probability of 2/5.

Hope this helps you!
nordsb [41]1 year ago
7 0

Answer:

Mason compared the number of free throws made to the number of free throws missed

Step-by-step explanation:

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