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2 years ago

Solve 7/4=3/x to the nearest tenth

Mathematics

2 answers:

trapecia [35]2 years ago

6 0

uhhh idk just ask ur teacher hehe

Tema [17]2 years ago

4 0

7:3 = 4:X
3X = 7×4
28 / 3 = X
X = 9.3
X ≈ 9.5

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You are in charge of a crew that inspects cars. Each car takes approximately 1/2 hour for 1 person to inspect. The normal crew h

jonny [76]

Answer:

Each inspectors NEEDS to work 20 hours in order to review 320 cars.

Step-by-step explanation:

The amount of time taken to inspect 1 car = 1/2 hr = 0.5 hr

The total people in crew are supposed to be 10

But 2 people are MISSING.

So, the total number of present people in crew = 10 - 2= 8

The total number of cars to be inspected = 320 cars.

Since each car takes 0.5 hour to be reviewed.

So, the time required to review 320 cars = 320 x 05 = 160 hours.

So, the total hours needed to inspect all 320 cars = 160 hours

Now,as there are total 8 crew members.

$\implies \textrm{The number of hours each inspector needs to work} = \frac{\textrm{Total working hours needed}}{\textrm{Toal number of inspectors}} \\= \frac{160}{8} = 20$

Hence , each inspectors NEEDS to work 20 hours in order to review 320 cars.

7 0

2 years ago

A group of friends are going ice skating. The price of admission is $3.25. As a group, they spent $14 on refreshments. If they s

Helen [10]

Start with $30.25.
Subtract $14.00 to isolate the amount of money spent on admission.
30.25-14.00= 16.25. As a group $16.25 was spent on admission.
Admission is 3.25 per person. Divide 16.25 by 3.25.
16.25/3.25=5.
5 friends went ice skating.

4 0

2 years ago

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Consider the dot plots which show the distribution of data collected on two high school basketball players. Which statement BEST

nadya68 [22]

I think the answer is d I haven’t done this in a while

6 0

2 years ago

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An angle bisector AC divides a trapezoid ABCD into two similar triangles △ABC and △ACD. Find the perimeter of this trapezoid if

LuckyWell [14K]

Answer:

46 cm

Step-by-step explanation:

It is given that the angle bisector AC divides the trapezoid ABCD into two similar triangles Δ ABC and Δ ACD.

Let us first find the corresponding sides of triangles Δ ABC and Δ ACD.

Since AC is the angle bisector of ∠A,

∠DAC = ∠CAB --- (1)

Also, since ∠DAC and ∠ACB are alternate interior angles,

∠DAC = ∠ACB --- (2)

From (1) and (2),

∠CAB = ∠ACB

Therefore, in Δ ABC,

BC = AB (sides opposite to equal angles are equal)

So, BC = 9 cm.

Now, since ∠DAC = ∠ACB and ∠DAC = ∠CAB, we can take either ∠ACB or ∠CAB as the angle corresponding to ∠DAC. Let us take ∠ACB as the corresponding angle of ∠DAC.

So, the side opposite to ∠DAC in Δ ACD is the corresponding side to the side opposite to ∠ACB in Δ ABC.

That is, the side CD in Δ ACD is the corresponding side to the side AB in Δ ABC.

Now, suppose if the side BC in Δ ABC corresponds to side AD of Δ ACD, then the remaining side AC of Δ ABC should correspond to side AC of Δ ACD which is not possible since they are congruent.

So, the side BC in Δ ABC should correspond to side AC of Δ ACD and the remaining side AC of Δ ABC should correspond to side AD of Δ ACD.

Therefore, we have,

$\frac{AB}{CD} =\frac{BC}{AC} =\frac{AC}{AD}$