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2 years ago

What is the value of x in the equation 1,331x3 − 216 = 0?

2 answers:

4 0

In solving for the value of x in the equation 1331x^3 - 216 = 0, the steps are shown below:

1331x^3 - 216 = 0
(1331x^3 = 216) / 1331
x^3 = 216/1331
x = cube root (216/1331)
x = 6/11

Therefore, the value of x in the equation is 6/11.

Bingel [31]2 years ago

4 0

Answer:

Value of $x =\frac{6}{11}$

Step-by-step explanation:

Given the equation: $1331x^3 -216 =0$ .....[1]

Addition property of equality states that you add the number to both sides of an equation.

Add 216 to both sides of an equation [1]

$1331x^3 -216+216 =0+216$

Simplify

$1331x^3=216$

As,we know that $11 \times 11 \times 11 =11^3 = 1331$ and $6 \times 6 \times 6 =6^3 = 216$

then the given equation becomes; $11^3x^3=6^3$

$(11x)^3=6^3$ ......[2]

Using $a^3=b^3$ then a=b.

[2] ⇒

11x =6

Divide both sides of an equation by 11, we get

$\frac{11x}{11} =\frac{6}{11}$

Simplify:

$x =\frac{6}{11}$

therefore, the value of x is, $\frac{6}{11}$

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1) $\frac{v(8)-v(0)}{8 - 0} = \frac{10-18}{8} = -1\frac{m}{s}$ .
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