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Wittaler [7]
2 years ago
15

What is the value of x in the equation 1,331x3 − 216 = 0?

Mathematics
2 answers:
Sphinxa [80]2 years ago
4 0
In solving for the value of x in the equation 1331x^3 - 216 = 0, the steps are shown below:

1331x^3 - 216 = 0
(1331x^3 = 216) / 1331
x^3 = 216/1331
x = cube root (216/1331)
x = 6/11

Therefore, the value of x in the equation is 6/11.

Bingel [31]2 years ago
4 0

Answer:

Value of x =\frac{6}{11}

Step-by-step explanation:

Given the equation: 1331x^3 -216 =0             .....[1]

Addition property of equality states that you add the number to both sides of an equation.

Add 216 to both sides of an equation [1]

1331x^3 -216+216 =0+216

Simplify

1331x^3=216

As,we know that  11 \times 11 \times 11 =11^3 = 1331 and 6 \times 6 \times 6 =6^3 = 216

then the given equation becomes;11^3x^3=6^3

or

(11x)^3=6^3                    ......[2]

Using  a^3=b^3 then a=b.

[2] ⇒

11x =6

Divide both sides of an equation by 11, we get

\frac{11x}{11} =\frac{6}{11}

Simplify:

x =\frac{6}{11}

therefore, the value of x is, \frac{6}{11}







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