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2 years ago

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A bag contains only red marbles and blue marbles. there are 6 marbles in the bag. the bag contains twice as many blue marbles as

red marbles. nadia takes one marble from the bag without looking. the probability that the marble is blue is

2 answers:

gtnhenbr [62]2 years ago

4 0

Let x=red, then blue=2x
x+2x=6
3x=6
x=2
2 red and 4 blue. the odds of drawing a blue is then 4/6, or 2/3, or approximately 66.7%

patriot [66]2 years ago

3 0

Answer:

Probability of getting blue = $\frac{2}{3}$ .

Step-by-step explanation:

Given : A bag contains only red marbles and blue marbles. there are 6 marbles in the bag. the bag contains twice as many blue marbles as red marbles. nadia takes one marble from the bag without looking.

To find : the probability that the marble is blue .

Solution : We have given

Total marble in beg = 6

Let the red marble = x

Blue = 2x .

So, x + 2x = 6.

3x = 6

On subtracting both sides by 3

x = 2.

Red marble = 2

Blue marbles are 4.

Probability of getting blue = $\frac{Blue\ marble}{Total\ marble}$ .

Probability of getting blue = $\frac{4}{6}$ .

Probability of getting blue = $\frac{2}{3}$ .

Therefore, Probability of getting blue = $\frac{2}{3}$ .

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The number of newly reported crime cases in a county in New York State is shown in the accompanying table, where x represents th

Novay_Z [31]

Answer:

Step-by-step explanation:

I use 84+ CE

stat edit, then fill in the #s

then

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then

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then, click stat

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then click (4)(LinReg(ax+b))

then click enter 5 times

(y=-25.31428571x+1000.285714

y=-25.3x+1000.3

now, lets use computer:

y=-25.31(543)+1000.3

y=-12743.03

round to the biggest whole number )

this doesn't really work, so I will put 1999, 2000, 2001, 2002, 2003, 2004 instead of 0, 1, 2, 3, 4, 5 and do the same thing

now I get

y=-25.31428571x+51603.54286

y=-25.3x+51603.5

now, lets use computer:

y=-25.3(543)+51603.5

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7 0

2 years ago

Ariana and Emily are both standing in line at Papa Joe’s Pizza. Ariana orders 4 large cheese pizzas and 1 order of breadsticks.

Eva8 [605]

The cost of 1 large pizza is $7.99 and cost of one breadstick is $2.50

Elimination method was used.

Step-by-step explanation:

Let,

Cost of one large pizza = x

Cost of one breadstick = y

According to given statement;

4x+y=34.46 Eqn 1

2x+y=18.48 Eqn 2

Subtracting Eqn 2 from Eqn 1

$(4x+y)-(2x+y)=34.46-18.48\\4x+y-2x-y=15.98\\2x=15.98$

Dividing both sides by 2

$\frac{2x}{2}=\frac{15.98}\\x=7.99$

Putting x=7.99 in Eqn 2

$4(7.99)+y=34.46\\31.96+y=34.46\\y=34.46-31.96\\y=2.50$

The cost of 1 large pizza is $7.99 and cost of one breadstick is $2.50

Elimination method was used.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

6 0

2 years ago

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

Viktor [21]

Answer:

Therefore $k= \frac{ln2 }{18}$ , A=184

Step-by-step explanation:

Given function is

$T(t)=230 -e^{-kt}$

where T(t) is the temperature in °C and t is time in minute and A and k are constants.

She noticed that after 18 minutes the temperature of the pie is 138°C

Putting T(t) =138°C and t= 18 minutes

$138=230 -Ae^{-k\times 18}$

$\Rightarrow -Ae^{-18k}=138-230$

$\Rightarrow Ae^{-18k}=92$ .....(1)

Again after 36 minutes it is 184°C

Putting T(t) =184°C and t= 36 minutes

$184=230-Ae^{-k\times 36}$

$\Rightarrow Ae^{-36k}=230-184$

$\Rightarrow Ae^{-36k}=46$ .......(2)

Dividing (2) by (1)

$\frac{Ae^{-36k}}{Ae^{-18k}}=\frac{46}{92}$

$\Rightarrow e^{-18k}=\frac{46}{92}$

Taking ln both sides

$ln e^{-18k}=ln\frac{46}{92}$

$\Rightarrow -18k =ln (\frac12)$

$\Rightarrow -18k= ln1-ln2$

$\Rightarrow k= \frac{ln2 }{18}$

Putting the value k in equation (1)

$Ae^{-18\frac{ln2}{18}}=92$

$\Rightarrow A e^{ln2^{-1}}=92$

$\Rightarrow A.2^{-1}=92$

$\Rightarrow \frac{A}{2}=92$

$\Rightarrow A= 92 \times 2$

⇒A= 184.

Therefore $k= \frac{ln2 }{18}$ , A=184

7 0

2 years ago

Tim Tradesman estimates his taxable income will be $7,500. He is paid every two weeks or 26 times a year.

alisha [4.7K]

Given:
Taxable income: 7,500
Paid every two weeks or 26 weeks in a year

Based on 2007 Federal Income Tax Table for Single Taxpayer, Tim is under the tax range over $0 but not over $7,825. The tax is 10% of the amount over $0.

<span>1. Finds the tax rate for his income level =10 %

2. Enters the base amount = $7,500

3. Enters the amount of tax owed = $7,500 * 10% = $750

4. Divides by 26 = $750 / 26 = $28.85 tax withheld from biweekly wages.</span>

8 0

2 years ago

Read 2 more answers

The New Mexico Division of Fish and Wildlife keeps track of the silvery minnow population in the Rio Grande River. They tagged 5

sattari [20]

Answer:

279 silvery minnow

Step-by-step explanation:

Number of Silvery Minnows initially tagged = 54

Number of minnows captured = 62

Number of tagged minnows in captured ones = 12

Remember that in the very beginning there were no tagged minnows. 54 minnows were captured, tagged and released. This means, there are total 54 tagged minnows in the entire population. Lets say there are x number of minnows in total.

So, in x minnows, 54 are tagged ones.

When 62 minnows are captured, only 12 are tagged ones and remaining are un-tagged. Since, the minnows were randomly captured, we can develop a proportion from this case to estimate the total population of minnows in the Rio Grande River.

Ratio of tagged minnows to total population must be equal to the ratio of captured tagged minnows in total captured minnows.

i.e.

$54 : x = 12 : 62\\\\ \frac{54}{x} = \frac{12}{62}\\\\ 62(54)=12x\\ \\ x = 279$

This means, there were 279 silvery minnows in the Rio Grande River.

3 0

2 years ago