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Dominik [7]
2 years ago
6

In the hexadecimal numbering system, the number 16 is expressed as _____.

Mathematics
2 answers:
Maksim231197 [3]2 years ago
4 0

Answer:

16 in hexadecimal is written as:

10 (1+0)

Step-by-step explanation:

The hexadecimal numeral system is a number system made up of 16 symbols or we say it is a base 16 number system.

In this number system, the digits have ones place, then sixteen's place, and the next 256's place and so on.

16 in hexadecimal is written as:

10 (1+0)

sladkih [1.3K]2 years ago
3 0

10
..........................

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First we need to calculate annual withdrawal of each investment
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PMT=pv÷[(1-(1+r)^(-n))÷(r)]

Now solve for the first investment
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Answer d

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6 0
2 years ago
jack puts 1/3 pound of birdseed into his feeder every time he fills it. how many can jack fill his bird feeder with 4 pounds of
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Answer: Jack can fill his feeder 12 times with 4 pounds of birdseed.

Step-by-step explanation:

You need to analize the information given in the exercise, You know that every time Jack fills the feeder, he put \frac{1}{3} pounds into it.

Then, in order to solve this exercise, let "x" represents the number of times that Jack can fill his  feeder with 4 pounds of birdseed.

Keeping on mind the data provided in the exercise, you can set up de following proportion:

\frac{1}{\frac{1}{3}} = \frac{x}{4}

Finally, you must solve for "x" in order to find its value.

You get that this  is:

3= \frac{x}{4}\\\\(3)(4)=x\\\\x=12

Therefore, you can conclude that Jack can fill his feeder 12 times with 4 pounds of birdseed.

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2 years ago
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astra-53 [7]
3.5/5=14/x   20ft tall
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Economists study the way society uses its resources. One important resource studied is agriculture. The recent increase in deman
Anon25 [30]

Answer:

Which is a reason that organic farming is more expensive than conventional farming?

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Step-by-step explanation:

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8 0
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Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (
kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2}) is given as continuous function, so there exist lim_{(x,y)\rightarrow(0,0)}f(x,y) and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19

So f(0,0)=ln19.

8 0
2 years ago
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