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yulyashka [42]
2 years ago
8

Theo can paint a fence three times as fast as his sister can. Working together, they can paint a fence in 9 hours. How many hour

s would it take Theo’s sister to paint the fence by herself?
Mathematics
1 answer:
Deffense [45]2 years ago
8 0

Answer:

12 hours

Step-by-step explanation:

Let Theo's siste can paint a fence in x times

Given.

Theo can paint a fence three times as fast as his sister can. Working together, they can paint a fence in 9 hours.

\frac{1}{x}+\frac{1}{3x} =\frac{1}{9}\\\frac{3+1}{3x} =\frac{1}{9} \\\frac{4}{3x}=\frac{1}{9}

Apply cross multiplication

x=\frac{9\times 4}{3}\\x=\frac{36}{3} \\x=12hours

Theo’s sister to paint the fence in 12 hours.

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Answer:

the correct answer is D

Step-by-step explanation:

if the 7 friends are splitting the cost they are dividing it among themselves.

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To add the two expressions, we can write it as:

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We can distribute the plus sign (which means just drop the parenthesis in this case):

4.6x-3-5.3x+9

Now, we can simplify by combining like terms:

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1/6,1/9,2/27,4/81 geometric sequence next value?
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If you would like to know the next value, you can calculate this using the following steps:

1/6, 1/9, 2/27, 4/81, x = ?

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So, if we would like to know what is the next value of this geometric sequence, you have to multiply 4/81 by 2/3:
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The correct result would be 8/243.
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During geometry class, students are told that ΔTSR ≅ ΔUSV. Marcus states that ΔTSR is mapped to ΔUSV by performing a rotation ab
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Answer: Both students are correct.

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In rotation a shape is rotated about a fixed point and it does not affect its measurements. it only changes its position.

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In reflection, when a shape reflected across a line then its all points get reflected across this line. But it also does not affect the measurement of the shape.

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There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
2 years ago
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