Answer:
And the critical value for the significance level used is:
Since the calculated value is less than the critical value we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the College graduation status and cola preference are independent
Step-by-step explanation:
For this case we want to test the following hypothesis:
Null hypothesis: College graduation status and cola preference are independent
Alternative hypothesis: College graduation status and cola preference are dependent
For this case we got a calculated statistic of:
And the critical value for the significance level used is:
Since the calculated value is less than the critical value we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the College graduation status and cola preference are independent
Answer:
(4+7i)-2i(2+3i) = 10+3i
Step-by-step explanation:
We need to find the expression that is equivalent to the complex number 10+3i.
Option 1. 2i(4-5i)+(1-7i)
=8i-10i²+1-7i
∵ i² = -1
=8i-10(-1)+1-7i
=8i+10+1-7i
=11+i (incorrect)
Option 2. (4+7i)-2i(2+3i)
=4+7i-4i-6i²
=4+7i-4i-6(-1)
=4+7i-4i+6
=10+3i (Correct)
Option 3. (-3+5i)-3i(4+5i)
= (-3+5i)-12i-15i²
= -3+5i-12i-15(-1)
= -3+5i-12i+15
=12-7i (incorrect)
Option 4. 3i(4+7i)+(11+2i)
= 12i+21i²+11+2i
=12i+21(-1)+11+2i
= 12i-21+11+2i
=14i-10 (incorrect)
Hence, the correct option is (B).
7a + 5a = 6a + 24
<span>6a = 24 </span>
<span>a = 4 </span>
<span>XZ = 6(4) + 24 </span>
<span>XZ = 48 </span>
Answer:
A
Step-by-step explanation:
Just took the quiz on edgenuity
Answer:
see below
Step-by-step explanation:
1.5x + 5y = 1152
x = 4y – 2
We can substitute the second equation into the first equation
Which one-variable linear equation can be formed using the substitution method?
1.5(4y-2) +5y = 1152
Distribute
6y -3 +5y = 1152
Combine like terms
11y-3 = 1152
Add 3 to each side
11y-3+3 = 1152+3
11y = 1155
Divide each side by 11
11y/11 = 1155/11
y = 105
How many $5 raffle tickets were sold?
105 5 dollar tickets were sold
Now we need to find the number of 1.50 tickets
Which equation can be used to determine how many $1.50 raffle tickets were sold?
x = 4y – 2
x = 4(105) -2
=420-2
= 418
How many $1.50 raffle tickets were sold?
418 $1.50 tickets were sold
