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Stels [109]
2 years ago
13

25.691 rounded to the greatest place

Mathematics
3 answers:
Mrac [35]2 years ago
8 0

To round off the value of 25. 691 to its greatest place. We first have to determine the highest order in the number which is tens. That is, 20. 000 = tens 5. 000 = ones 0. 600 = tenths 0. 090 = hundredths 0. 001 = thousandths.

Conclusively, the value of 25. 691 if we round it off will be 30. 000 (tens place). Notice the rounding off rules of 5-9.

Hope this helps!

Guest
1 year ago
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Alona [7]2 years ago
6 0
The answer for this equation is 25
Guest
1 year ago
what tge fucckkckckkcc
Guest1 year ago
0 0

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Oliga [24]

Let

x-------> the length of the rectangle

y------> the width of the rectangle

we know that

The area of the rectangle is equal to

A=x*y

The area of the two congruent right triangles  is equal to the area of the rectangle

A=2*44=88\ in^{2}

so

88=x*y -------> equation A

y=x-3 -----> equation B

Substitute equation B in equation A

x*[x-3]=88

x^{2} -3x-88=0 --------> equation that can be used  to solve for the length of the rectangle

Using a graph tool-------> solve the quadratic equation

see the attached figure

The solution is

x=11\ in -----> the length of the rectangle

Find the value of y

88=11*y

y=8\ in  ----> the width of the rectangle

Statements

<u>case A)</u> The area of the rectangle is 88 square inches

The statement is True

See the procedure

<u>Case B)</u> The equation  x*[x-3]=44 can be used to solve for the dimensions of the triangle

The statement is False

Because, the equation x*[x-3]=88 can be used to solve for the dimensions of the triangle

<u>case C)</u> The equation x^{2} -3x-88=0 can be used to solve for the length of the rectangle

The statement is True

see the procedure

<u>case D)</u>The triangle has a base of 11 inches and a height of 8 inches

The statement is True

Because, the base of the triangle is equal to the length of the rectangle and the height of the triangle is equal to the width of the rectangle

<u>case E)</u> The rectangle has a width of 4 inches

The statement is False

See the procedure

8 0
2 years ago
Read 2 more answers
Employees that work at a fish store must measure the level of nitrites in the water each day. Nitrite levels should remain lower
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Answer: .0039

Step-by-step explanation:

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2 years ago
Your friend is trying to grow her hair as long as her cousin’s hair. The table shows their hair lengths y (in inches) in differe
Effectus [21]
<span>Given the table that shows the hair lengths y (in inches) of your friend and her cousin in different months x.

Month      Friends Hair(in)      Cousins Hair(in)
    3                     4                              7
    8                    6.5                            9.

To solve for the cousins hair, recall that the equation of a line is given by

y = mx + c

From the table,

7 = 3m + c . . . (1)
9 = 8m + c . . . (2)

(1) - (2) ⇒ -2 = -5m
\Rightarrow m= \frac{2}{5} =0.4

Substituting for m into equation (1) gives:

7=3(0.4)+c \\  \\ \Rightarrow c=7-1.2=5.8

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2 years ago
The negative sign in 15t-2t belongs to the term____?
alexdok [17]

The expression 15t – 2t not equivalent to 2t – 15t because the negative sign in 15t – 2t belongs to the term 2t.

Solution:

Given expressions are 15t – 2t and 2t – 15t.

To determine 15t – 2t is equivalent to 2t – 15t or not.

Substitute t = 2 in above two expressions.

15t – 2t = 15(2) – 2(2)

            = 30 – 4

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2t – 15t = 2(2) – 15(2)

            = 4 – 30

            = –26

The values of the expressions are different when t = 2.

So, 15t – 2t is not equivalent to 2t – 15t.

Hence the expression 15t – 2t not equivalent to 2t – 15t because the negative sign in 15t – 2t belongs to the term 2t.

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2 years ago
A wild animal generally stays at least x mi from the edge of a forest. For a rectangular forest preserve that is 2 mi
Butoxors [25]

Answer:

Area = 4x^2 - 14x + 10

Step-by-step explanation:

<em>See Attachment for Complete Question</em>

Given

Width = 5mi --- For the forest

Length = 2mi -- --- For the forest

Required

Determine the area of the habitat

Since the distance between the animal's habitat is x mi on both sides;

The length and width of the habitat is:

Width = 5 - (x + x)

Width = 5 - 2x

Height = 2 - (x +x)

Height = 2 - 2x

The area is then calculated as follows;

Area = Width * Height

Area = (5 - 2x) * (2 - 2x)

Expand

Area = 5(2 - 2x) -2x(2 - 2x)

Open Brackets

Area = 10 - 10x - 4x + 4x^2

Area = 10 - 14x + 4x^2

Reorder

Area = 4x^2 - 14x + 10

Hence; the required polynomial for the habitat area is:

Area = 4x^2 - 14x + 10

3 0
2 years ago
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