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musickatia [10]
1 year ago
6

Two children are sharing 1/2 of a sandwich. how much will each child get

Mathematics
1 answer:
11Alexandr11 [23.1K]1 year ago
6 0

Each child will get 1/4 of the sandwich.

(1/2)/2 = 1/4

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Three hundred high school seniors were surveyed about their intended college majors. The results are displayed in the Venn Diagr
atroni [7]

Answer: \frac{1}{10}

Step-by-step explanation:

Since, The total number of student = 300

Out of which,

The number of students who are only in Maths  = 120

And, The number of students who are only in Science  = 50

While, the students who are not from any subject = 100

Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None

= 300 - 120 - 50 - 100

= 30

That is, there are 30 students who are both from science and maths,

Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10

3 0
1 year ago
Read 2 more answers
Charlotte’s weekly paycheck is based on the number of hours worked during the week and on the weekend. If she works 13 hours dur
Gelneren [198K]
I am setting the week hourly rate to x, and the weekend to y.  Here is how the equation is set up:

13x + 14y = $250.90
15x + 8y = $204.70

This is a system of equations, and we can solve it by multiplying the top equation by 4, and the bottom equation by -7.  Now it equals:

52x + 56y = $1003.60
-105x - 56y = -$1432.90

Now we add these two equations together to get:

-53x = -$429.30 --> 53x = $429.30 --> (divide both sides by 53) x = 8.10.  This is how much she makes per hour on a week day.

Now we can plug in our answer for x to find y.  I am going to use the first equation, but you could use either.

$105.30 + 14y = $250.90.  Subtract $105.30 from both sides --> 14y = $145.60 divide by 14 --> y = $10.40

Now we know that she makes $8.10 per hour on the week days, and $10.40 per hour on the weekends.  Subtracting 8.1 from 10.4, we figure out that she makes $2.30 more per hour on the weekends than week days.
7 0
1 year ago
Read 2 more answers
The graph shown below expresses a radical function that can be written in the form f(x)=a(x+k)^1/n+c. What does the attached gra
Sergeeva-Olga [200]

The attached graph tells me that the domain is [-k,∞) and the range of this function is  (-∞,c]. The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query about this specific question.

4 0
1 year ago
Read 2 more answers
A small town's phone numbers either begin 373 or 377. How many phone numbers are available?
ser-zykov [4K]

Answer:

  • <u><em>There are 20,000 number available.</em></u>

Explanation:

To determine <em>how many phone numbers are available </em>you need to know how many digits the number contains.

I will assume the same number of digits for other similar questions, i.e. 7.

With 7 digits, the numbers that begin with 373 or 377 can be of the form 373XXXX or 377XXXX.

Where each X can be any digit 0 - 9. Then, there are 10 different options for each X.

Thus, there are 10×10×10×10 = 10,000 different numbers starting with 373 and other 10,000 different numbers starting with 377.

In total, there are 20,000 numbers available.

6 0
1 year ago
Problem 5 (4+4+4=12) We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Fin
tekilochka [14]

Answer:

1

p(b) =  \frac{1}{6}

2

p(k) =  \frac{1}{3}

3

P(a) =  \frac{1}{3}

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

n = 36

Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

p(b) =  \frac{N}{n}

p(b) =  \frac{6}{36}

p(b) =  \frac{1}{6}

Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)

Looking at this outcome we see that there are two doubles present

So

The conditional probability that doubles were rolled is mathematically represented as

p(k) =  \frac{2}{6}

p(k) =  \frac{1}{3}

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

So

The conditional probability that at least one die is a 1 is mathematically represented as

P(a) =  \frac{W}{L}

=> P(a) =  \frac{10}{30}

=> P(a) =  \frac{1}{3}

3 0
1 year ago
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