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2 years ago

Why did Maggie not have flood insurance? Check all that apply.

Business

2 answers:

romanna [79]2 years ago

7 0

CDE are the answers to this question.

Galina-37 [17]2 years ago

3 0

The correct answer is C, D, E.

C. She felt she needed to save money.

D. She may have misunderstood her basic homeowners policy.

E. Her expenses were already high before paying for insurance.

Flood insurance it has specific insurance coverage which is to insure for a property if lost from flooding.

Insurers first they check from topographical map so as to know the floodways which are susceptible for flooding, flood plains and low lands.

Number of claimants is larger in flood insurance than those who are interested protect their property.

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Jason and his family were invited to dinner by a family friend who had just opened a high-end restaurant. Jason and his family w

mixer [17]

Answer:

C) is the answer in my opinion

7 0

2 years ago

Read 2 more answers

Mr. Rich arranged for a mortgage loan for 65 percent of the $2.5 million purchase price of a home. The monthly payment will be $

olga2289 [7]

Answer:

Effective annual rate = 6.82 %

Explanation:

given data

loan = 65 % of $2.5 million = $1625000

monthly payment pmt = $10,400

time = 30 year = 30 × 12 = 360

solution

we get here rate first by present value

present value = pmt × $\frac{1-(1+r)^{-t}}{r}$ ..........1

$1625000 = $10400 × $\frac{1-(1+r)^{-360}}{r}$

15.625 = $\frac{1-(1+r)^{-360}}{r}$

solve it we get

r = 0.5517%

and Effective annual rate will be

Effective annual rate = $(1+r)^{12} -1$

Effective annual rate = $(1+0.005517)^{12} -1$

Effective annual rate = 0.068250

Effective annual rate = 6.82 %

7 0

2 years ago

Warner Company's year-end unadjusted trial balance shows accounts receivable of $99,000, allowance for doubtful accounts of $600

dsp73

Explanation:

The journal entry to record the uncollectible is shown below:

On December 31

Bad debt expense $800

To Allowance for doubtful debts $800

(Being the bad debt expense is recorded)

The computation is shown below:

= Sales × estimated percentage - credit balance of doubtful accounts

= $280,000 × 0.5% - $600

= $1,400 - $600

= $800

5 0

2 years ago

Blue Ridge Bicycles uses a standard part in the manufacture of several of its bikes. The cost of producing 45,000 parts is $14

Morgarella [4.7K]

Answer:

$2.07 per unit

Explanation:

Currently 45,000 units produced

total cost= $72,000 (variable) + $70,000 (fixed) = $142,000

average total cost per unit = $142,000 / 45,000 units = $3.16 per unit

if the company outsources the production of the part:

total cost = $72,000 + ($70,000 x 30%) = $72,000 + $21,000 = $93,000

average total cost per unit = $93,000 / 45,000 units = $2.07 per unit

if Blue Ridge spends more than $2.07 per unit, it will be spending more money by outsourcing the part than by producing it.

e.g. $2.10 per unit

total costs = ($2.10 x 45,000) + ($70,000 x 70%) = $94,500 + $49,000 = $143,500 which is higher than $142,000.

3 0

2 years ago

Each of 16 students measured the circumference of a tennis ball by four different methods, which were:

antoniya [11.8K]

Question Continuation

a. Compute the mean measurement for each method.

b. Compute the median measurement for. each method.

c. Compute the 20% trimmed mean measurement for each method.

Answer:

a. Mean

Mean A = 22.675

Mean B = 20.71875

Mean C = 21.0125

Mean D = 20.86875

b. Median

Median A = 23.45

Median B = 20.45

Median C = 21.0

Median D = 20.7

c. 20% Trimmed Mean

Trimmed Mean A = 23.14

Trimmed Mean B = 20.73

Trimmed Mean C = 21.04

Trimmed Mean D = 20.75

Explanation:

Mean = Σx/n

Where Σx= Summation of entries in each method

n = 16

Mean of Method A = (18.0 + 18.0 +18.0 + 19.0 + 22.0 + 22.0 + 22.5 + 22.9 + 24.0 + 24.0 + 25.0 +25.0 + 25.0 + 25.0 + 26.0 +26.4)/16

Mean A = 362.8/16

Mean A = 22.675

Mean of Method B = (18.8 + 18.9 + 18.9 + 19.8 + 20.1 + 20.4 + 20.4 + 20.4 + 20.6 + 20.5 + 21.2 + 21.9 + 22.0 + 22.0 + 22.0 + 23.6)16

Mean B = 331.5/16

Mean B = 20.71875

Mean of Method C = (20.2 + 20.5 + 20.5 + 20.7 + 20.8 + 20.9 + 21.0 + 21.0 + 21.0 + 21.0 + 21.0 + 21.5 + 21.5 + 21.5 + 21.5 + 21.6)/16

Mean C = 336.2/16

Mean C = 21.0125

Mean of Method D = (20.0 + 20.0 + 20.0 + 20.2 + 20.2 + 20.5 + 20.5 + 20.7 + 20.7 + 20.7 + 21.0 + 21.5 + 21.5 + 21.6 + 22.1 + 22.3)/16

Mean D = 333.9/16

Mean D = 20.86875

Median is the number(s) at the middle

Since the total number of points for each method is 16 and this is an even number we need to calculate the median as the average between the 8th and the 9th position of the data ordered from the smallest to the largest. If we do this we have that:

Method A

Arranged Data: 18.0, 18.0, 18.0, 19.0, 22.0, 22.0, 22.5, 22.9, 24.0, 24.0, 25.0, 25.0, 25.0, 25.0, 26.0, 26.4

The 8th and 9th data are: 22.9 and 24.0

Median = (22.9 + 24.0/2

Median = 46.9/2

Median A = 23.45

Method B

Arranged Data: 18.8, 18.9, 18.9, 19.8, 20.1, 20.4, 20.4, 20.4, 20.5, 20.6, 21.2, 21.9, 22.0, 22.0, 22.0, 23.6

The 8th and 9th data are: 20.4 and 20.5

Median = (20.4+20.5)/2

Median = 40.9/2

Median B = 20.45

Method C

Arranged Data: 20.2, 20.5, 20.5, 20.7, 20.8, 20.9, 21.0, 21.0, 21.0, 21.0, 21.0, 21.5, 21.5, 21.5, 21.5, 21.6

The 8th and 9th data are: 21.0 and 21.0

Median = (21.0 + 21.0)/2

Median = 42.0/2

Median C = 21.0

Method D

Arranged Data: 20.0, 20.0, 20.0, 20.2, 20.2, 20.5, 20.5, 20.7, 20.7, 20.7, 21.0, 21.5, 21.5, 21.6, 22.1, 22.3

The 8th and 9th data are: 20.7 and 20.7

Median = (20.7+20.7)/2

Median = 41.4/2

Median D = 20.7

The trimmed mean by 20% means that we'll calculate mean by removing the 20% from each of the tails.

20% of 16 = 3.2 (Approximated to 3)

So we need to remove 3 observations from both ends of the data.

Method A becomes

19.0, 22.0, 22.0, 22.5, 22.9, 24.0, 24.0, 25.0, 25.0, 25.0

Trimmed Mean A = (19.0+22.0+22.0+22.5+ 22.9+24.0+24.0+25.0+ 25.0+ 25.0)/10

Trimmed Mean A = 231.4/10

Trimmed Mean A = 23.14

Method B becomes

19.8, 20.1, 20.4, 20.4, 20.4, 20.6, 20.5, 21.2, 21.9, 22.0

Trimmed Mean B = (19.8+20.1+20.4+ 20.4+ 20.4+20.6+20.5+21.2+21.9+22.0)/10

Trimmed Mean B = 207.3/10

Trimmed Mean B = 20.73

Method C becomes

20.7, 20.8, 20.9, 21.0, 21.0, 21.0, 21.0, 21.0, 21.5, 21.5

Trimmed Mean C = (20.7+ 20.8+ 20.9+ 21.0+ 21.0+ 21.0+21.0+, 21.0+, 21.5+21.5)/10

Trimmed Mean C = 210.4/10

Trimmed Mean C = 21.04

Method D becomes

20.2, 20.2, 20.5, 20.5, 20.7, 20.7, 20.7, 21.0, 21.5, 21.5

Trimmed Mean D = (20.2+, 20.2+20.5+, 20.5+ 20.7+ 20.7+ 20.7 +, 21.0 +21.5 + 21.5)/10

Trimmed Mean D = 207.5/10

Trimmed Mean D = 20.75

7 0

2 years ago