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balandron [24]
2 years ago
4

Select all that apply. The Insert menu provides access to which of the following tasks? Illustrations Comments Options Headers a

nd Footers
Computers and Technology
2 answers:
IgorC [24]2 years ago
8 0

Answer:

Insert menu provides access to:

  • illustrations
  • comments
  • headers and footers

Explanation:

Insert menu provides access to many tasks which includes tables and chart as well as the above mentioned tasks but it doesn't provide access to the options task .

Insert Menu is critical part of the Microsoft office because it is an HTML command that can be executed by clicking on the insert menu to add as many attachable files like text,pictures. under the insert menu we have sub menus like the text section which contains the symbols and word Art options.  

Mamont248 [21]2 years ago
5 0

The Insert menu provides access to the following tasks :

Illustrations

Comments

Headers and Footers

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Splunk uses ________ to categorize the type of data being indexed..
timama [110]
<span>Splunk is the system process that handles indexing, searching, forwarding and the web interface for Splunk Enterprise.</span>
Splunk uses sourcetypes to categorize the type of data being indexed.
Splunk supports the Common Information Model (CIM). 
7 0
2 years ago
Read 2 more answers
Which of the following is true about protected access?
goldenfox [79]

Answer:(A) Protected members may be accessed by methods in the same package or in a subclass, even when the subclass is in a different package.

Explanation:

Methods,constructors and variables, that are protected in superclass they can be only accessed by any class within the package of the protected members class and methods in the same package or they can be of a subclass or the subclasses that may be present in other package .

5 0
2 years ago
Given three dictionaries, associated with the variables, canadian_capitals, mexican_capitals, and us_capitals, that map province
Nookie1986 [14]

Answer:

The Python code to combine the three dictionaries are is given as follows:

  1. canadian_capital = {
  2.    cash: "SOME VALUES",
  3.    assets: "SOME VALUES"
  4. }
  5. mexican_capital = {
  6.    cash: "SOME VALUES",
  7.    assets: "SOME VALUES"
  8. }
  9. us_capital = {
  10.    cash: "SOME VALUES",
  11.    assets: "SOME VALUES"
  12. }
  13. nafta_capital = {
  14.    canadian: canadian_capital,
  15.    mexican : mexican_capital,
  16.    us: us_capital
  17. }

Explanation:

<u>Line 1 - 14 :</u>

Create three Python dictionaries and name them as <em>canadian_capitals, mexican_capital </em>and<em> us_capitals</em>. Please note a Python dictionaries should be enclosed in curly braces { }.  

We just define two samples of relevant keys (<em>cash </em>and <em>asset</em>) in each of the dictionaries. Python dictionary can map a key to a value.

Since we are not given any capital values from the question,  a dummy string "<em>SOME VALUES</em>" is tentatively set as the value for each of the keys.

In practice, we should replace those dummy strings with the real values of capital. The values can be a number, a string, a list and even a nested dictionary.

<u>Line 16 - 20 : </u>

Create one more Python dictionary and name it as <em>nafta_capital</em>.

Since our aim is to combine the three previous dictionaries (<em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em>) and associate it with <em>nafta_capital</em>, we can define three different keys (<em>canadian, mexican </em>and <em>us</em>) in our dictionary nafta_capital.

As mentioned, a value associated with a key can be a nested dictionary. Hence, we just map <em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em> as the value of the keys (<em>canadian, mexican </em>and<em> us</em>) in dictionary<em> nafta_capital,</em> respectively,

By doing so, we have managed to combine three target dictionaries (<em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em> ) into a single dictionary, <em>nafta_capital</em>.

4 0
2 years ago
The major result of treating 1-butyne with 6M aqueous NaOH would be:_______.A. the production of an alkene.B. the production of
andriy [413]

Answer:

D. nothing, as the alkyne would not react to an appreciable extent.

Explanation:

Nothing, as the alkyne would not react to an appreciable extent.

6 0
2 years ago
9. Which of the following are true for all regular languages and all homomorphisms? (a) h (L1 ∪ L2)= h (L1) ∩ h (L2). (b) h (L1
mixer [17]

Answer:

h (L1 ∪ L2)= h (L1) ∩ h (L2).

This is true.

There will be w ∈  (L1 ∪ L2) for any s ∈ h (L1 ∪ L2) in such a way that s=h(w)

we can assume that w ∈ L1

So In this case h(w) ∈ L (S1). Hence s ∈ L(S1)

for any s ∈ h (L1) U h(L2)

We can assume that s ∈ L(S1)

There exists w ∈ L1 such that s= h(w)

In this case it is w ∈ L1 U L2 as well.

Hence , s ∈ h (L1 U L2)

Explanation

consider  = 0,1 and  = a,b and h(0) = a , h(1) = ab

(a) Consider L1 = 10,01 and L2 = 00,11

   Now L1 ∪ L2 = 00,01,10,11

   h (L1 ∪ L2) = h(00) , h(01) , h(10) , h(11) = h(0)h(0) , h(0)h(1) , h(1)h(0) , h(1)h(1)

  = aa, aab , aba , abab

Hence h (L1 ∪ L2) = aa, aab , aba , abab .

Here h (L1) = h(10) , h(01) = h(1)h(0) , h(0)h(1) = aba , aab

Hence h (L1) = aba , aab .

Here h (L2) = h(00) , h(11) = h(0)h(0), h(1)h(1) = aa, abab

Hence h(L2) = aa, abab.

Finally Hence , h (L1 ∪ L2)= h (L1) ∩ h (L2).

5 0
2 years ago
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