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N76 [4]
2 years ago
15

A pumpkin has a mass of 314 ounces. Based on the tiles below, what is the mass of the pumpkin in kilograms?A. 0.0111 kg

Physics
2 answers:
Nataly [62]2 years ago
7 0

Answer:

Mass of the pumpkin, m = 8.9 kg

Explanation:

It is given that,

Mass if pumpkin, m = 314 ounces

We need to find the mass of the pumpkin. We need to find the mass of the pumpkin in kilograms. The relation between ounce and kilograms is as follows :

1 ounce = 0.0283495 kg

We will now use the unitary method for finding the mass of the pumpkin.

314 ounce = 8.90 kilograms

So, the mass of the pumpkin is 8.9 kg. Hence, this is the required solution.  

Katyanochek1 [597]2 years ago
5 0
The mass of the pumpkin in kilograms is 8.90 kg
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ioda

Answer:

L' = 1.231L

Explanation:

The transmission coefficient, in a tunneling process in which an electron is involved, can be approximated to the following expression:

T \approx e^{-2CL}

L: width of the barrier

C: constant that includes particle energy and barrier height

You have that the transmission coefficient for a specific value of L is T = 0.050. Furthermore, you have that for a new value of the width of the barrier, let's say, L', the value of the transmission coefficient is T'=0.025.

To find the new value of the L' you can write down both situation for T and T', as in the following:

0.050=e^{-2CL}\ \ \ \ (1)\\\\0.025=e^{-2CL'}\ \ \ \ (2)

Next, by properties of logarithms, you can apply Ln to both equations (1) and (2):

ln(0.050)=ln(e^{-2CL})=-2CL\ \ \ \ (3)\\\\ln(0.025)=ln(e^{-2CL'})=-2CL'\ \ \ \ (4)

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\frac{ln(0.050)}{ln(0.025)}=\frac{-2CL}{-2CL'}=\frac{L}{L'}\\\\0.812=\frac{L}{L'}\\\\L'=\frac{L}{0.812}=1.231L

hence, when the trnasmission coeeficient has changes to a values of 0.025, the new width of the barrier L' is 1.231 L

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2 years ago
Which of the following strategies can help Earth's coal supply last longer?
ivanzaharov [21]
D. Teach the public energy conservation
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Although blood cells are contained within a special liquid called plasma, the cells themselves are___________.
valentina_108 [34]

Answer:

Solid

Explanation:

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2 years ago
The U.S. Department of Energy had plans for a 1500-kg automobile to be powered completely by the rotational kinetic energy of a
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230

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\omega = Rotational speed = 3600 rad/s

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Charge q1 is distance r from a positive point charge q. charge q2=q1/3 is distance 2r from q. what is the ratio u1/u2 of their p
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<span>The potential energy of charge q is proportional to </span>
<span>∫[s=r to ∞] qQs⁻²ds = -qQs⁻¹|[s=r to ∞] = qQr⁻¹, </span>

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<span>= 4•3 = 12.</span>
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2 years ago
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