Answer:
Momentum, p = 7.2 g-m/s
Explanation:
It is given that,
The momentum of an object is 
We need to express momentum in any equivalent units. There can be many solutions of this problem. Some of the units of mass are gram, milligram etc. units of length are meters, mm etc.
Since, 1 kg = 1000 gram
So, 
Therefore, the momentum of the object is 7.2 g-m/s. Hence, this is the required solution.
Answer:

Explanation:
Given that
Length= 2L
Linear charge density=λ
Distance= d
K=1/(4πε)
The electric field at point P



So

Now by integrating above equation

Answer: 9.08KW and 16.21KW
Explanation:
The convection over a flat surface with a length of 10 m and a width of 6m.
The mean temperature is (5oC + 12oC)/2 = 8.5oC.
Then find the following properties of air at this temperature from Table A-15:
k = 0.02428 W/m(oC, v= 1.413x10-5 m2/s, and Pr = 0.7340.
find the Reynolds number. Re= VL/v
Check screenshot
This means that the flow becomes turbulent over the plate and we can use the Nusselt number equation for combined laminar and turbulent flow.
Check screenshot
We then use this Nusselt number to find the heat transfer coefficient and the heat transfer.
Check the screen shot for the calculation
Ans
9.08 kW
Then if the wind velocity were doubled, the Re number would be doubled and we would repeat the calculations above, starting with this revised Reynolds number..
Ans
16.21 kW
The first law of thermodynamics says that the variation of internal energy of a system is given by:

where Q is the heat delivered by the system, while W is the work done on the system.
We must be careful with the signs here. The sign convention generally used is:
Q positive = Q absorbed by the system
Q negative = Q delivered by the system
W positive = W done on the system
W negative = W done by the system
So, in our problem, the heat is negative because it is releaed by the system:
Q=-1275 J
while the work is positive because it is performed by the surrounding on the system:
W=+855 J
So, the variation of internal energy of the system is
Answer:
Two identical spheres are released from a device at time t = 0 from the same ... Sphere A has no initial velocity and falls straight down. ... (b) On the axes below, sketch and label a graph of the horizontal component of the velocity of sphere A and of sphere B as a function of time. ... Which ball has the greater vertical velocity
Explanation: