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Amiraneli [1.4K]
1 year ago
5

Charge q1 is distance r from a positive point charge q. charge q2=q1/3 is distance 2r from q. what is the ratio u1/u2 of their p

otential energies due to their interactions with q?
Physics
1 answer:
makvit [3.9K]1 year ago
5 0
We need the power law for the change in potential energy (due to the Coulomb force) in bringing a charge q from infinity to distance r from charge Q. We are only interested in the ratio U₁/U₂, so I'm not going to bother with constants (like the permittivity of space). 

<span>The potential energy of charge q is proportional to </span>
<span>∫[s=r to ∞] qQs⁻²ds = -qQs⁻¹|[s=r to ∞] = qQr⁻¹, </span>

<span>so if r₂ = 3r₁ and q₂ = q₁/4, then </span>
<span>U₁/U₂ = q₁Qr₂/(r₁q₂Q) = (q₁/q₂)(r₂/r₁) </span>
<span>= 4•3 = 12.</span>
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The momentum of an object is determined to be 7.2 × 10-3 kg⋅m/s. Express this quantity as provided or use any equivalent unit. (
slavikrds [6]

Answer:

Momentum, p = 7.2 g-m/s

Explanation:

It is given that,

The momentum of an object is p=7.2\times 10^{-3}\ kg-m/s

We need to express momentum in any equivalent units. There can be many solutions of this problem. Some of the units of mass are gram, milligram etc. units of length are meters, mm etc.

Since, 1 kg = 1000 gram

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2 years ago
A charged wire of negligible thickness has length 2L units and has a linear charge density λ. Consider the electric field E-vect
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Answer:

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

Explanation:

Given that

Length= 2L

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r^2=d^2+x^2

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E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

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2 years ago
during a cold winter day, wind at 42 km/h is blowing parallel to a 6-m-high and 10-m-high wall of a house. If the air outside is
Arturiano [62]

Answer: 9.08KW and 16.21KW

Explanation:

The convection over a flat surface with a length of 10 m and a width of 6m.

The mean temperature is (5oC + 12oC)/2 = 8.5oC.

Then find the following properties of air at this temperature from Table A-15:

k = 0.02428 W/m(oC, v= 1.413x10-5 m2/s, and Pr = 0.7340.

find the Reynolds number. Re= VL/v

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This means that the flow becomes turbulent over the plate and we can use the Nusselt number equation for combined laminar and turbulent flow.

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We then use this Nusselt number to find the heat transfer coefficient and the heat transfer.

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Ans

9.08 kW

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Ans

16.21 kW

4 0
2 years ago
A system delivers 1275 j of heat while the surroundings perform 855 j of work on it. calculate ∆esys in j.
kakasveta [241]
The first law of thermodynamics says that the variation of internal energy of a system is given by:
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So, the variation of internal energy of the system is
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6 0
2 years ago
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jeka94

Answer:

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