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d1i1m1o1n [39]
2 years ago
11

mr. martin’s math test, which is worth 100 points, has 29 problems. each problem is worth either 5 points or 2 points. let x be

the number of questions worth 5 points and let y be the number of questions worth 2 points. x y = 29, 5x 2y = 100 how many problems of each point value are on the test? 10 problems worth 5 points and 25 problems worth 2 points 14 problems worth 5 points and 15 problems worth 2 points 16 problems worth 5 points and 13 problems worth 2 points 15 problems worth 5 points and 13 problems worth 2 points
Mathematics
2 answers:
Yakvenalex [24]2 years ago
5 0
The Answer would be <span>14 problems worth 5 points and 15 problems worth 2 points</span>
wariber [46]2 years ago
4 0
Let x and y be the numbers of questions worth 5 and 2, respectively. There are a total of 29 questions which means that x + y should be 29. The equations that best describe the conditions are,
                                      x + y = 29
                                     5x + 2y = 100
Solving for x and y gives x = 14 and y = 15. Thus, there are 14 and 15 questions worth 5 and  2, respectively.
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A fisherman catches fish according to a Poisson process with rate lambda = 0.6 per hour. The fisherman will keep fishing for two
spayn [35]

Answer:

Step-by-step explanation:

Given that a fisherman catches fish according to a Poisson process with rate lambda = 0.6 per hour.

The fisherman will keep fishing for two hours.

Since he continues till he gets atleast one fish, we can calculate probability as follows:

(a) Find the probability that he stays for more than two hours.

= Prob (x=0) in I two hours and P(X≥1) in 3rd hour

=P(x=0)*P(X=0)*P(X≥1) (since each hour is independent of the other)

= 0.5488^2*(1-0.8781)\\\\=0.2645

(b) Find the probability that the total time he spends fishing is between two and five hours.

Prob that he does not get fish in I two hours * prob he gets fish between 3 and 5 hours

=P(0)^2 *F(1)^3\\=0.5488^2*0.2645^3\\=0.00557

(c) Find the expected number offish that he catches.

Expected value in Geometric distribution = \frac{1-p}{p}, where p = prob of getting 1 fish in one hour

= \frac{0.6}{1-0.6} \\=3

(d) Find the expected total fishing time, given that he has been fishing for four hours.

= Expected fishing time total/expected fishing time for 4 hours

=3/0.6*4

= 1.25 hours

4 0
2 years ago
Six pairs of socks cost as much as 1 coat, 2 pairs of jeans cost as much as 3 pairs of shoes, and 4 pairs of socks cost as much
REY [17]
(1) 6 pairs of socks = 1 coat
(2) 2 pairs of jeans = 3 pairs of shoes
(3) 4 pairs of socks = 1 pair of jeans

the last two points are irrelevant becuase we just need socks and coats. 
6 pairs of socks are equal to 1 coat. 
we need 64 pairs of socks. 
so, 64 ÷ 6 = 10.67

so we'll need 10.67 coats for 64 pairs of socks. 

i'm not sure if you've typed up the correct numbers becuase i don't think the answer would be expressed as a decimal. 

unless we say that we need 11 pairs of coats? 

perhaps reread the question again and make sure you've typed it up correctly
xD i hope i've helped. 
7 0
2 years ago
Doug has a bag full of crayons. There are 6 red crayons, 7 blue ones, and 4 green crayons. Doug wants to color a blue sky. What
larisa86 [58]

Answer:

Blue 7/17 = Nearly 0.41

Red 6/17= Nearly 0.35

4/17= Nearly 0.23

Step-by-step explanation:

The Probability is 13/17 if im wrong then sorry i havent done this in a while

8 0
2 years ago
What value is equivalent to 2 × 3 + 4 − 62?<br> A) -26 <br> B) -22 <br> C) -2 <br> D) 10
deff fn [24]

Hello from MrBillDoesMath!

Answer:

-52. None of the provided choices is correct

Discussion:

Following the usual order of math operations none of the provided answers is correct. The answer is

2*3 + 4- 62 =                => * before + and -

(2*3) + 4 - 62=             => 2*3 = 6

6 + 4 -62 =                   => 6 + 4 = 10

10 - 62 =

-52

Thank you,

MrB

6 0
2 years ago
Read 2 more answers
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densk [106]
A) He wanted to create zero pairs on the left side of the equation to get a positive coefficient of x on the right side
7 0
2 years ago
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