The answer is Desalination. Desalination is the process of removing minerals from salt water. Most ocean-water consumption and supply are most likely to be very particular in this places like USA, Europe, Africa and UN. Desalination depends on the capacity and facility of the place.
Answer:
100 units
Explanation:
The interphase of the cell cycle includes three stages: G1, S, and G2. During the S phase of interphase, the cell enters the process of DNA replication. DNA replication duplicates the existing DNA molecule and doubles the DNA content of the cell. The cell accommodates the newly formed DNA in two sister chromatids of chromosomes. If a cell of grasshopper contained 200 units of DNA in the G2 phase, the cell would have 100 units of DNA in the G1 phase. The S phase would have doubled the DNA content and the G2 phase had 200 units.
Less of the sugars produced in the leaves is used making cellulose, the structural molecule that supports stems in herbaceous plants. As a result, more is free to be stored in grain in the form of starch. Hope this helps! :D<span>
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Diet and weight-loss companies create the illusion of isolation, as if everyone else has met the ideal beauty standard and that “you aren’t right now, but you can too!” Instead of focusing on the health of the customer, these companies promote their methods of weight-loss before any other. Use skepticism if an advertisement makes claims that seem “too good to be true”, are scientifically unsubstantiated, only provide one perspective/way of thinking, or appear to prioritize sales over health.
This is the DNA. I'm going to only use the upper strand to demonstrate what this strand would code for before and after a single bp deletion (so write it as mRNA). I will also write it how it's easier to see this which is to split them up into the 3 base codon system. Note that you don't need to know the amino acid code - you use a table to find these.
ORIGINAL (mRNA on top, Amino Acid (AA) on bottom:
5'-AGC GGG AUG AGC GCA UGU GGC GCA UAA CUG-3'
SER GLY MET SER ALA CYS GLY ALA STOP LEU
Note that the protein would stop being made at the stop codon and the LEU wouldn't matter at the end...
Now, I will remove one bp...(I bolded it up top). Rewrite the mRNA and find the corresponding AA...
NEW
5'-AGC GGG AUG GCG CAU GTG GCG CAU AAC UG-3'
SER GLY MET ALA HIS VAL ALA HIS ASN .....
Completely different amino acid sequence after the methionine (MET). The stop codon is gone...the protein would continue being translated until it reaches another stop codon...so not what was supposed to be made!
