Answer:
Ben - Y Xc
Jen - XCXC
Violet - XCXc
Seraphina - XCXc
Samuel- Y Xc
Explanation:
Given -
Ben has a cleft chin
Let the allele for cleft chin be "c"
and the allele for normal chin be "C"
When Ben with cleft chin mates with wife Jennifer Garner having normal chin, then the two girl child do not have cleft chin but the boy has cleft chin.
This means that the allele C could be X -linked and the mother is not the carrier but the father is
The genotype of father Ben would be Y Xc
Genotype of mother would be XCXC
Genotype of two daughters XCXc , XCXc which means they are carrier for the next generation
Genotype of Boy - Y Xc
Full question found from other source
The F2 generation phenotypes for each cross are shown in Table 1. (See attachment) Which of the following is the mean number per cross of F2 generation offspring that are the result of crossing over?
Answer:
B, 2.2
Explanation:
The parental genotypes are long and black vs short and white. Therefore the phenotypes that result from crossing over are long and white, and short and black. (middle two rows of the table). If we add up the total number of offspring with these genotypes we get 6 long whites, and 5 short blacks.
The total is 11 from 5 crosses, so the mean is 11/5 = 2.2
Answer:
C) Bacteria congregated in these areas because these areas had the most oxygen being released.
Explanation:
Below is the full question:
Theodor W. Engelmann illuminated a filament of algae with light that passed through a prism, thus exposing different segments of algae to different wavelengths of light. He added aerobic bacteria and then noted in which areas the bacteria congregated. He noted that the largest groups were found in the areas illuminated by the red and blue light.
What did Engelmann conclude about the congregation of bacteria in the red and blue areas?
A) Bacteria released excess carbon dioxide in these areas.
B) Bacteria congregated in these areas due to an increase in the temperature of the red and blue light.
C) Bacteria congregated in these areas because these areas had the most oxygen being released.
D) Bacteria are attracted to red and blue light and thus these wavelengths are more reactive than other wavelengths.
E) Bacteria congregated in these areas due to an increase in the temperature caused by an increase in photosynthesis.
The most efficient region of white light for photosynthesis has been found to be the blue and red region of the white light. Hence, these two regions must have had the most oxygen being released because they are the regions with the highest rates of photosynthesis.
<em>Aerobic bacteria thrived better in the regions illuminated by red and blue light because these regions had the highest oxygen production as a result of having the highest rates of photosynthesis.</em>
<em>The correct option is C.</em>
Answer:
The options
A. the postzygotic barrier called hybrid inviability
B. the postzygotic barrier called hybrid breakdown
C. the prezygotic barrier called hybrid sterility
D. gametic isolation
The CORRECT ANSWER IS A.
A. the postzygotic barrier called hybrid inviability
Explanation:
Postzygotic barrier is a mechanism that hinders reproduction after fertilization and zygote development. Hybrid inviability occurs when a mating between two organism produces a hybrid that can't strive past the embryonic stages.
In Reduced Hybrid Viability there is a lower tendency to survive for individuals whose parents possesses incompatible genetics, which may have result from sexual union of these parents from varying species.
These two frog species in this case study can be separated through the mechanism of the postzygotic barrier called hybrid inviability.
