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makvit [3.9K]
2 years ago
11

One afternoon the water park sold 525 tickets for a total of $13,545 . Child tickets cost $19 each, and adult tickets cost $40 e

ach. How many of each kind of ticket were sold?
Mathematics
2 answers:
Marina86 [1]2 years ago
8 0
You need to set up 2 problems for this. Let’s start with the # of tickets sold & variables.

c = # of child tickets sold
a = # of adult tickets sold

c + a = 525

Now we need to set up the equation for the money.

c = # of child tickets sold
a = # of adult tickets sold

19c + 40a = 13,545

Now put the two equations by each other.

c + a = 525
19c + 40a = 13,545

Now I will solve for one of the variables.

c + a = 525
-a -a

c = 525 - a

Now I plug it into the other equation.

19(525) + 40a = 13,545
Solve.
9,975 + 40a = 13,545
-9,975
40a = 3,570 / 40
a = 89.25
89 rounded?

then plug in a on the second equation

c + 89 = 525
-89 -89
c = 436

so the answer is:
Sold 89 adult tickets.
Sold 436 kids tickets.
Setler79 [48]2 years ago
5 0

Answer: The no of child and adult are 355 and 170 respectively


Step-by-step explanation:

Let the no of tickets for child be x

and the no of tickets for adult be y

Given x+y=525.........[1]

19x+40y=13545.........[2]

Multiplying  [1] by 19

19x+19y=9975........[3]

Subtracting [3] from [2]

19x+40y-19x -19y= 13545-9975

21y=3570

Dividing both sides by 21

y=170

Putting value of y in [1]

x+170=525

Subtracting 170 both sides

x+170-170= 525-170

x=355

No of child =355

No of adults =170


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