I = PRT.....rearrange = I / PR = T
I = 450
R = 7.5%...turn to decimal = 0.075
P = 2400
I / (PR) = T
450 / (2400 * 0.075) = T
450 / 180 = T
2.5 = T...so time is 2.5 years, or 2 1/2 years
Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.
The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.
Answer:
Option b
Step-by-step explanation:
Given that the probability distribution of X, where X is the number of job applications completed by a college senior through the school’s career center.
Expected observed Diff
x p(x) p(x)*1000
0 0.002 2
1 0.011 11 14 -3
2 0.115 115 15 100
3 0.123 123 130 -7
4 0.144 144
5 0.189 189
6 0.238 238
7 0.178 178
1 1000
We find that there is a large difference in 2 job application
Hence option b is right.
2.8y + 6 + 0.2y = 5y – 14
Simplify the left side:
3y +6 = 5y-14
Subtract 3y from both sides:
6 = 2y -14
Add 14 to each side:
2y =20
Divide both sides by 2:
y = 20 / 2
y = 10
Given:
Pyramid A: Base is rectangle with length of 10 meters and width of 20 meters.
Pyramid B: Base is square with 10 meter sides.
Heights are the same.
Volume of rectangular pyramid = (L * W * H) / 3
Volume of square pyramid = a² * h/3
Let us assume that the height is 10 meters.
V of rectangular pyramid = (10m * 20m * 10m)/3 = 2000/3 = 666.67 m³
V of square pyramid = (10m)² * 10/3 = 100m² * 3.33 = 333.33 m³
The volume of pyramid A is TWICE the volume of pyramid B.
If the height of pyramid B increases to twice the of pyramid A, (from 10m to 20m),
V of square pyramid = (10m)² * (10*2)/3 = 100m² * 20m/3 = 100m² * 6.67m = 666.67 m³
The new volume of pyramid B is EQUAL to the volume of pyramid A.