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sergij07 [2.7K]
2 years ago
5

How many moles of pbr3 contain 3.68 Ã 1025 bromine atoms?

Chemistry
1 answer:
Vikentia [17]2 years ago
3 0

<u>Given data:</u>

# atoms of Br in PBr3 = 3.68 * 10^25

<u>Explanation:</u>

In PBr3,

1 mole of PBr3 contains 3 moles of Br

Now,

1 mole of Br contains Avogadro number i.e. 6.023 * 10^23 atoms of Br

Therefore, the # moles of Br corresponding to 3.68*10^25 atoms would be:

= 3.68 * 10^25 atoms * 1 mole Br/6.023*10^23 atoms = 61.099 moles of Br

Since,

3 moles of Br is present in 1 mole of PBr3

then, 61.099 moles of Br would correspond to:

61.099 moles Br * 1 mole PBr3/3 moles Br = 20.366 moles of PBr3

<u>Ans: 20.4 moles of PBr3</u>

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