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1 year ago

1. Control of temperature, endocrine activity, metabolism, and thirst are functions associated with (1 point)

2 answers:

8 0

The answer to this question is breathing, heart beating, walking, and talking. It is because the autonomic nervous system is connected to peripheral nervous systems that control the function of internal organs such as the heart and other bodily activities.

dybincka [34]1 year ago

3 0

1. Control of temperature, endocrine activity, metabolism, and thirst are functions associated with the hypothalamus. The correct option among all the options is the third option.

2. "Heart beating" is the one among the following that is an example of a function that is performed exclusively by the autonomic nervous. The correct option among the options given is the second option.

3. The diffusion of potassium out of a neuron causes it to experience depolarization. The correct option among the options given is the second option.

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Match the following vocabulary words. 1.ciliary musclesA transparent liquid which is located between the cornea and iris. 2.opti

klio [65]

Answer:

1. Aqueous humor.

2. Ciliary muscles.

3. Cone.

4. Cornea.

5. Iris.

6. Optic nerve.

7. Photoreceptor.

8. Retina.

9. Rod.

10. Sclera.

11. Vitreous humor.

Explanation:

A sensory system can be defined as components of the central nervous system (CNS) which comprises of the brain, neural tissues or pathways and sensory neurons responsible for sensory functions, perception and processing sensory informations such as sound, light, heat, etc.

Basically, the central nervous system (CNS) interprete the neural signals that are generated from stimuli that are detected by the sensory system. The five (5) main sense organs in the sensory system are: skin, tongue, ears, nose and the eyes.

An eye can be defined as a specialized organ of sight with the capability to receive visual images that are subsequently transduced into neural signals and relayed to the brain for processing and interpretation. Some of the components of the human eye matched with their description are;

1. Aqueous humor: a transparent liquid which is located between the cornea and iris.

2. Ciliary muscles: muscles attached to the lens to change its shape.

3. Cone: a photoreceptor cell which functions best in bright light. It detects color.

4. Cornea: the transparent portion of the sclera at the front of the eye.

5. Iris: a special part of the choroid layer composed of colorful tissue.

6. Optic nerve: the nerve connecting the eye to the brain.

7. Photoreceptor: specialized cells located in the retina that receive light images.

8. Retina: a delicate light-sensitive membrane covering the inside of the eyeball.

9. Rod: a photoreceptor cell which is sensitive to dim light, but detects no color.

10. Sclera: a fibrous material surrounding the eye to give it shape.

11. Vitreous humor: a transparent jellylike substance filling the eyeball.

8 0

1 year ago

Read 2 more answers

11) A patient has had a serious accident and lost a lot of blood. In an attempt to replenish body fluids, distilled water, equal

tino4ka555 [31]

C.
The blood fluid contains less water, which will cause the water to go into the cells and make them swell up.

8 0

2 years ago

The interaction between two polar molecules would involve ________.

denpristay [2]

The interaction between two polar molecules would involve HYDROGEN BONDS.
Polar molecules are molecules that have both positive and negative charges as a result of the differences in the electronegativity of the atoms that made up the molecule. Polar molecules interact through dipole dipole inter molecular forces and hydrogen bonds.

7 0

1 year ago

In this example, we used lotka-volterra equations to model populations of rabbits and wolves. let's modify those equations as fo

Daniel [21]

Answer:

Wolves absence would lead the rabbit population to become stable at 5,000.

Explanation:

Step 1. Concept

If there is a missing variable that should be in the system, set that particular variable to zero and make the necessary conclusion.

Step 2. Given,

dR/dt = 0.08R(1 - 000.2R) - 0.001RW

dW/dt = −0.02W + 0.00002RW

Step 3. Calculation

The transformed equations of populations of rabbit and wolves will be

dR/dt = 0.08R(1 - 000.2R) - 0.001RW

dW/dt = −0.02W + 0.00002RW

Let's check the rabbit population in the absence of wolves(W) to 0

Thus,

Differential equation dR/dt

dR/dt = 0.08R(1 - 000.2R) - 0.001RW

Take W to equal to O

dR/dt = 0.08R(1 - 000.2R) - 0.001R(0)

dR/dt = 0.08R(1 - 000.2R)

When,

dR/dt = 0 we have R = 0 or R = 5,000

This,

R = 5,000 becomes the equilibrium point in the absence of wolves

Then,

0 < R < 5,000, dR/dt > 0

For R, let's estimate a value rise of the rabbit population to 5,000

Then,

R > 5,000, dR/dt < 0

Judging from the value if R, we infer a deduction in the rabbit population by 5,000

Thus,

We can conclude that wolves absence would lead the rabbit population to become stable at 5,000.

7 0

1 year ago

The action potential propagates along the sarcolemma. as the action potential spreads down the t tubules of the triads, voltage-

Ganezh [65]

It permits calcium to leave the sarcoplasmic reticulum and enter the cytosol. During muscle contraction, the binding of acetylcholine initiates an excitatory impulse, which is transmitted to the deep of the muscle via T tubules. T tubules are the invaginations of cell membranes of muscle cells (sarcolemma). When the action potential travel down the t-tubules, they change shape and allow the calcium ions to enter into the sarcoplasm from the sarcoplasmic reticulum.

6 0

1 year ago