The answer is 49.92%
Let's use the <span>Hardy-Weinberg principle:
p + q = 1
p</span>² + 2pq + q² = 1
<span>
where:
p - the frequency of dominant allele G
q - </span>the frequency of recessive allele g
p² - the frequency of homozygous dominant individuals GG with colour green
2pq - the frequency of heterozygous individuals Gg with colour green
p² - the frequency of homozygous recessive individuals gg with color brown
23% of the population is brown: p² = 23% = 0.23
p = √(p²) = √0.23 = 0.48
p = 0.48
p + q = 1
0.48 + q = 1
q = 1 - 0.48 = 0.52
<span>The percentage of the population that is expected to be heterozygous is 2pq:
2pq = 2 * p * q = 2 * 0.48 * 0.52 = 0.4992 = 49.92%</span>
Answer: genus
Explanation:
The answer to the question is genus. The genus is where microevolution occurs or happens. The domain, species, kingdom, family, or population are not the taxonomic category where microevolution occurs. The answer to the question is genus.
Have a nice day!
4^3 = 64
There are 64 ways to arrange the four bases (Adenine, Thymine, Cytosine, and Guanine) into triplets (include repeats of bases as well, for e.g. AAT).
Just in case you are confused by my use of Thymine above, one thing to note is that Thymine will be replaced with Uracil in RNA.
Hope this helps! :)
In this question, the ant has 4 pairs of chromosomes. Each pair of chromosomes will be separated in a gamete, resulting 4 unpaired chromosomes. That is why gamete is called haploid or n.
That means only 1 of the 2 chromosomes that will be carried into a gamete, assuming the gene heterozygote then there would be 2 possibilities. Since each chromosome pairs can produce 2 possibilities for each male or female, their interaction will result as (2x2) 4 possibilities.
Then for 4 chromosomes would be 4^4 possibilities= 256 possibilities of offspring