A biologist wants to test the rate of absorption into several different types of

In multicellular organisms,the cell cycle produces groups of cells that perform the same function. What are these cells called?

Anon25 [30]

Organs, cells with the same function make up tissue and tissue makes up the organ

8 0

2 years ago

Scientists are studying the structure and function of receptor x, a single-polypeptide protein that is found in the membrane aro

svetlana [45]

Answer:

This protein doesn't have a secondary structure (i.e., alpha helices or beta sheets), thereby it interacts with the specific molecule trough its loops

Explanation:

Protein loops may interact with diverse molecules including nucleic acids (RNA and DNA), proteins, signal molecules, etc. These protein sequences (loops) interact with both polar and non-polar head groups

5 0

2 years ago

What type of protist is heterotrophic and includes species whose cells can come together to form a slug that moves to a new habi

Reil [10]

Answer: Fungus like protists are heterotrophic and feed on organic matter.

Cellular slime mould is a species of fungus like protists that form slug.

Explanation:

Fungus like protists are heterotrophic and the feed on organic matter and mostly unicellular.

Cellular slime mould are protists belonging to class Dictyostelia. They are heterotrophic and decomposers that live on organic matter. When there is deterioration condition, the cells migrates together to form slugs and move to form new habitat. Some of the cells form stalk and others form spores.

8 0

2 years ago

Two autosomal genes, J and K, are 60 map units apart. You perform the following testcross: J K / j k x j k / j k. At what freque

Dmitry [639]

Answer:

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%

Explanation:

To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.

The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.

So, en the exposed example:

J and K are autosomal genes

J and K are separated by 60 M.U.

60 M.U. means that there is 60% of recombination.

Cross) J K / j k x j k / j k

Gametes) JK Parental jk, jk, jk, jk

jk Parental

Jk Recombinant

jK Recombinant

One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.

1 M.U. -------------- 1% recombination

60 M.U. ------------ 60% recombination

30% Jk + 30% jK

100 M.U. - 60 M.U. = 40 M.U.

40M.U.--------------40 % Parental (Not recombinant)

20% JK + 20% jk

Punnet Square) JK jk Jk jK

jk JK/jk jk/jk Jk/jk jK/jk

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%

3 0

2 years ago

A species was added into a particular ecosystem to control the population of a prey species. This method of introducing a new sp

Natasha2012 [34]

1- Bioremedation (When you add a species to an ecosystem its not native to.

2- The competition for resources increased in the ecosystem.

4 0

2 years ago

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