Her school is 2/3 miles away
2/3=4/6miles
So we need to find out how long it will take for her to run home from school...
School=4/6 miles
In 1 minutes she can run 1/6 miles
1min=1/6miles
In 2 minutes she can run 1/6+1/6 miles (1/6+1/6=2/6)
2min=2/6miles
3min=3/6miles
4min=4/6miles
It will take Erica 4 minutes to run 4/6 miles, so it'll take her 4 minutes to get home.
<span>Chaneece chooses x as the larger number and uses the inequalities y ≤ 40 – x and y ≤ x – 20 to determine the possible solutions.
</span>y ≤ 40 – x, if x must be between 0 and 10, y must be between 20 and 40 <span>it is true
proof
</span><span>for x=0 and y=10, y ≤ 40 – x equivalent to 10<40-0=40 it is true
</span>x=10, y=30, <span>y ≤ 40 – x equivalent to 30=40-10=30 it is true
the answer is </span><span>A) Yes, Chaneece found the correct solution. </span>
Answer:
H(t) = 15 -6sin(2.5π(t -0.5))
Step-by-step explanation:
For midline M, amplitude A, period T and time t0 at which the function is decreasing from the midline, the function can be written as ...
H(t) = M -Asin(2π/T(t -t0))
Using the given values of M=15, A=6, T=0.8 and t0 = 0.5, the equation is ...
H(t) = 15 -6sin(2.5π(t -0.5))
The side length of the square concrete slab if the area is increased by 25% is 5feet
The formula for calculating the area of a square is expressed as:
A = L² where:
L is the side length of the square
Given the area of the square concrete slab = 20 square feet
20 = L²
L =√20
If the area is increased by 25%, new area will be:
An = 20 + (0.25*20)
An = 20 + 5
An = 25 sq.ft
Get the new length
An = Ln²
25 = Ln²
Ln = √25
Ln = 5feet
Hence the side length of the square concrete slab if the area is increased by 25% is 5feet
Learn more here: brainly.com/question/11300671