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2 years ago

11

Greg has a school debt of $9875. he wants to make biweekly payments and pay off the loan in four years. if the intrest rate is 6

.3% compounded biweekly, how much are his payments?

1 answer:

tatuchka [14]2 years ago

3 0

Greg would the payments of $15,553.13. I think or $2,222

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A property valued at $295,000 has a gross rent multiplier of 135. What is this property's monthly income? $2,458,$2,185,$2,525 O

velikii [3]

This is your formula:
$135 = \frac{295000}{x}$
solve for x and your answer is:
$x = 2185$

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2 years ago

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5. The measures of angles of hexagon are 4x, 5x, 6x, 7x, 8x and 9x. Calculate the size of the largest angle

Amiraneli [1.4K]

Answer:

166 2/13 deg

Step-by-step explanation:

The sum of the measures of the interior angles of a convex polygon of n sides is 180(n - 2).

A hexagon has 6 sides, so n = 6.

sum of measures of angles = 180(n - 2) = 180(6 - 2) = 180(4) = 720

4x + 5x + 6x + 7x + 8x + 9x = 720

39x = 720

x = 720/39

x = 240/13

The largest angle has measure 9x.

9x = 9 * 240/13 = 2160/13

2160/13 = 166 2/13

Answer: 166 2/13 deg

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2 years ago

Keith_Richards [23]

Answer:

a

Step-by-step explanation:

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2 years ago

Trip walks a total of 12 miles to and from school each week. Lindsey rides her bike a total of 56 miles to and from school each

Ulleksa [173]

I don't quite understand the question but the total number of miles is 68

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2 years ago

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The endpoints of JK are J(–25, 10) and K(5, –20). What is the y-coordinate of point L, which divides JK into a 7:3 ratio? a. –16

Andrews [41]

let's say the point dividing JK is say point P, so the JK segment gets split into two pieces, JP and PK

$\bf ~~~~~~~~~~~~\textit{internal division of a line segment} \\\\\\ J(-25,10)\qquad K(5,-20)\qquad \qquad \stackrel{\textit{ratio from J to K}}{7:3} \\\\\\ \cfrac{J~~\begin{matrix} P \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} P \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~K} = \cfrac{7}{3}\implies \cfrac{J}{K} = \cfrac{7}{3}\implies3J=7K\implies 3(-25,10)=7(5,-20)\\\\[-0.35em] ~\dotfill$

$\bf P=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] ~\dotfill\\\\ P=\left(\cfrac{(3\cdot -25)+(7\cdot 5)}{7+3}\quad ,\quad \stackrel{\textit{y-coordinate}}{\cfrac{(3\cdot 10)+(7\cdot -20)}{7+3}}\right) \\\\\\ P=\left( \qquad ,\quad \cfrac{30-140}{10} \right)\implies P=\left(\qquad ,~~\cfrac{-110}{10} \right)\implies P=(\qquad ,\quad -11)$

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2 years ago

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