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Svetlanka [38]
2 years ago
7

A board 120 inches long is divided into 2 sections. If the ratio of the 2 sections is 3:5, what are the lengths of the sections?

Mathematics
1 answer:
riadik2000 [5.3K]2 years ago
3 1

Answer: D.45 inches, 75 inches

Step-by-step explanation:

Hi, to answer this question, first, we have to divide the board's length by the number of parts that conforms the 2 sections.

Since the ratio is 3/5, one section is made of 3 parts and the other section is made of 5 parts. 3+5 = 8 parts

120 / 8 = 15 inches

Each part measures 15 inches.

Now, we have to multiply each part's length by the number of parts that each section has. (3 and 5)

15x 3 = 45 inches

15 x 5 = 75 inches

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Suppose that the weight of seedless watermelons is normally distributed with mean 6.1 kg. and standard deviation 1.9 kg. Let X b
horrorfan [7]

Answer:

a. X\sim N(\mu = 6.1, \sigma = 1.9) b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349

Step-by-step explanation:

a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.

b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.

c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842

d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166

e. The z-score related to 6.4 kg is z_{1} = (6.4-6.1)/1.9 = 0.1579 and the z-score related to 7 kg is z_{2} = (7-6.1)/1.9 = 0.4737, we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194

f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349

7 0
2 years ago
An online news source reports that the proportion of smartphone owners who use a certain operating system is 0.216. Two simulati
kaheart [24]

Answer:

The center/ mean will almost be equal, and the variability of simulation B will be higher than the variability of simulation A.

Step-by-step explanation:

Solution

Normally, a distribution sample is mostly affected by sample size.

As a rule, sampling error decreases by half by increasing the  sample size four times.

In this case, B sample is 2 times higher the A sample size.

Now, the Mean sampling error is affected and is not higher for A.

But it's sample is huge for this, Thus, they are almost equal

Variability of simulation decreases with increase in number of trials. A has less variability.

With increase number of trials, variability of simulation decreases, so A has less variability.

4 0
2 years ago
Use technology to approximate the solution(s) to the system of equations to the nearest tenth of a unit.
kherson [118]

Answer:

  • A.)  (3.6, 0.6)
  • D.)  (2.6, 0.4)

Step-by-step explanation:

See below for a graph.

___

Choices B, C, E can be eliminated on the basis that neither x nor g(x) can be negative. The domain of f(x) is x>0; the range of g(x) is x≥0.

7 0
2 years ago
Binks needs to raise at least $3600. He was given $200 and plans to save $50 a week. Select all of the inequalities that represe
kherson [118]

Answer:

I'm pretty sure it is 50n+200 <u><</u> 3600

Step-by-step explanation:

Im to fully sure tho

5 0
1 year ago
A model spaceship costs $15.99 before tax. The tax on the model spaceship is 8%. What is the total cost of the model spaceship?
yan [13]
Model spaceship cost = $15.99
Tax % = 8%

Amount of tax = 15.99*0.08 = $1.279

Amount after tax = $15.99+$1.279 = 17.2692
After rounding-off to the nearest cent, it would be $17.27

So, your final answer is $17.27

Hope this helps!
6 0
2 years ago
Read 2 more answers
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