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2 years ago

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Company B Loses $1,575 for every employee who quit before 90days, What what is the total amount the company will lose if 2 emplo

yees quit before 30days, 1 employee quits on day 41 , and 1 employee quits on day 100

1 answer:

Sergeu [11.5K]2 years ago

5 0

Answer: The total amount is $4,725.

Step-by-step explanation:

1. Based on the information given in the problem, when an employee quit before 90 days, the company loses $1,575.

2. Then, the number of employees that quit before 90 days were:

$(2+1)=3$ employees

3. To calculate the total amount that the company will lose if these 3 employees quit before 90 days, you must multiply 3 employees by $1,575, as following:

$total=(3)(1,575dollars)\\total=4,725dollars$

4. The result is $4,725.

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Shtirlitz [24]

Answer:

24 hours

Step-by-step explanation:

Let m represent motorcycles and h represent hours it takes to make the motorcycles

$6m=9h$

$12m = 18h$

$9 \div6=1.5$

$1m = 1.5h$

$1.5 +1.5+1.5+1.5=$

$1.5+1.5=3.0$

$3.0+3.0=6.0$

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Therefore it takes "24 hours" to create 16 motorcycles.

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2 years ago

For the binomial expansion of (x + y)^10, the value of k in the term 210x 6y k is a) 6 b) 4 c) 5 d) 7

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Answer:

a) 6

Step-by-step explanation:

Expanding the polynomial using the formula:

$(x+y)^n=\sum_{k=0}^n \binom{n}{k} x^{n-k} y^k$

Also

$\binom{n}{k}=\frac{n!}{(n-k)!k!}$

I think you mean $210x^6y^4$

We can deduce that this term will be located somewhere in the middle. So I will calculate $k= 5; k=6 \text{ and } k =7$ .

For $k=5$

$\binom{10}{5} (y)^{10-5} (x)^{5}=\frac{10!}{(10-5)! 5!}(y)^{5} (x)^{5}= \frac{10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5! }{5! \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 } \\ =\frac{30240}{120} =252 x^{5} y^{5}$

Note that we actually don't need to do all this process. There's no necessity to calculate the binomial, just $x^{n-k} y^k$

For $k=6$

$\binom{10}{6} \left(y\right)^{10-6} \left(x\right)^{6}=\frac{10!}{(10-6)! 6!}\left(y\right)^{4} \left(x\right)^{6}=210 x^{6} y^{4}$

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