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balu736 [363]
2 years ago
4

Line WY is dilated to create line W'Y' using point Q as the center of dilation. What is the scale factor? Given that QY' = 4.125

, what is QY?
Mathematics
2 answers:
BlackZzzverrR [31]2 years ago
5 0

What is the scale factor?          2.75

Given that QY' = 4.125, what is QY?       1.5

Readme [11.4K]2 years ago
3 0

So,  WY = k × W'Y'

Line WY is Dilated to create line W'Y'.

Pre image = WY

Image = W'Y'

WY = k× W'Y', where k is amount of dilation done .

If WY > W'Y' , then k<1.

And , WY < W'Y' then k>1.

Q is center of Dilation.

→W'Y' =2  × QY' = 2 ×4.125 = 8.250

WY = k × W'Y' where k is amount of dilation.

→2 × QY = k × 2×QY'

→ QY = k× 4.125= 4.125 k

→ k(Factor Dilation) = \frac{WY}{W'Y'} =\frac{8.250}{\text{Length of line segment WY}}

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Margarita [4]
A)

total of balls = 8+6+10= 24 balls 

3/24= .125 and it is 12.5 % that one of the orange balls is 5 because it is an odd number.

B) 

4/24 =.167 0r 16.7% that of the gray balls is numbered 8.


6 0
2 years ago
On average, the number of customers who had items to return for refunds or exchanges at a certain retail store's service desk is
spayn [35]

Answer:

The probability that the service desk will have at least 100 customers with returns or exchanges on a randomly selected day is P=0.78.

Step-by-step explanation:

With the weekly average we can estimate the daily average for customers, assuming 7 days a week:

M=756/7=108

We can model this situation with a Poisson distribution, with parameter λ=108. But because the number of events is large, we use the normal aproximation:

P(\lambda)\approx N(\lambda,\lambda)

Then we can calculate the z value for x=100:

z=\frac{x-\mu}{\sigma}=\frac{100-108}{\sqrt{108}}=\frac{-8}{10.4} =-0.77

Now we calculate the probability of x>100 as:

P(x>100)=P(z>-0.77)=0.78

The probability that the service desk will have at least 100 customers with returns or exchanges on a randomly selected day is P=0.78.

5 0
2 years ago
Para ingresar a la Universidad del Chocó se aplica una prueba de razonamiento que consta de 30 preguntas. Por cada respuesta cor
s2008m [1.1K]

Complete question:

Para ingresar a la Universidad del Chocó se aplica una prueba de razonamiento que consta de 30 preguntas. Por cada respuesta correcta se asignan 5 puntos y por cada incorrecta (o no contestada) se restan 2 puntos. Si un participante obtuvo un puntaje de 94 puntos, ¿cuantas preguntas respondió bien?

Responder:

número de respuestas correctas = 22

Explicación paso a paso:

Dado lo siguiente:

Número total de preguntas = 30

Deje respuestas correctas = y; Respuestas incorrectas = n

Marca otorgada por y = 5

Marca deducida por n = 2

Si el total de preguntas = 30; luego

y + n = 30 - - - - (1)

Puntuación total obtenida = 94; luego

5y - 2n = 94 - - - (2)

De 1),

y + n = 30

y = 30 - n

Sustituya y = 30 - n en equ (2)

5 (30 - n) - 2n = 94

150 - 5n - 2n = 94

150 - 7n = 94

-7n = 94-150

-7n = - 56

n = 56/7

n = 8

Sustituir n = 8 en (1)

y + n = 30

y + 8 = 30

y = 30 - 8

y = 22

y = número de respuestas correctas = 22

n = número de respuestas incorrectas = 8

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Answer:

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Step-by-step explanation:

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