I think the answer is 1,600 totals students taking metaphysics
Answer:
We need the grid to figure this out
Answer:
Step-by-step explanation:
The problem relates to filling 8 vacant positions by either 0 or 1
each position can be filled by 2 ways so no of permutation
= 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2
= 256
b )
Probability of opening of lock in first arbitrary attempt
= 1 / 256
c ) If first fails , there are remaining 255 permutations , so
probability of opening the lock in second arbitrary attempt
= 1 / 255 .
Answer:
A) Yes, because P (F∩S) = 0
Step-by-step explanation:
Hello!
50 customers of a store were asked to choose between two discounts:
Discount 1: 20% off all purchases for the day.
Discount 2: 10% off all purchases for the week.
28 choose discount 1
22 choose discount 2
F: the selected person choose discount 1.
S: the selected person choose discount 2.
Two events are mutually exclusive when the occurrence of one of them prevents the other from occurring in one repetition of the trial and the intersection between these two events is void with zero probability of happening.
In this case, since the customers were asked to choose one out of the two events, if the customer chooses the first one, then he couldn't have chosen the second one and vice-versa. Then the intersection between these two events has zero probability, symbolically:
P(F∩S)=0
I hope it helps!
Let L be the length of one side of Kamila's bedroom (since her bedroom is square, the area would be L x L). Then the width of her living room is 1.25L. So:
18*1.25L=2.5(L)²
22.5L=2.5L²
L=22.5/2.5=9
Kamila's bedroom is 9'x9'; her living room is 11.25'x18'. ☺☺☺☺
