From my research, the image attached supports the problem. Since only the outer curve is to be solved for, the formula for arcs can be used.
s = theta*radius
where s = arc length = outer curve
theta = 70 (pi/180)
radius = 70
s = 70 * (70*pi/180)
s = 85.52 feet
Therefore, the outer curve is 85.52 feet long
Step-by-step explanation:
A is the correct answer of this question
X - the number of sandwiches ordered
y - the number of soups ordered
There were 18 people, and each person ordered either one soup or one sandwich.

The sandwiches cost $7.75 each, the soups cost $4.50 each. The total cost was $113.50.

Set up a system of equations:

10 sandwiches were ordered.
The answer is D.
Answer:
The variance in weight is statistically the same among Javier's and Linda's rats
The null hypothesis will be accepted because the P-value (0.53 ) > ∝ ( level of significance )
Step-by-step explanation:
considering the null hypothesis that there is no difference between the weights of the rats, we will test the weight gain of the rats at 10% significance level with the use of Ti-83 calculator
The results from the One- way ANOVA ( Numerator )
with the use of Ti-83 calculator
F = .66853
p = .53054
Factor
df = 2 ( degree of freedom )
SS = 23.212
MS = 11.606
Results from One-way Anova ( denominator )
Ms = 11.606
Error
df = 12 ( degree of freedom )
SS = 208.324
MS = 17.3603
Sxp = 4.16657
where : test statistic = 0.6685
p-value = 0.53
level of significance ( ∝ ) = 0.10
The null hypothesis will be accepted because the P-value (0.53 ) > ∝
where Null hypothesis H0 = ∪1 = ∪2 = ∪3
hence The variance in weight is statistically the same among Javier's and Linda's rats