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Scrat [10]
2 years ago
9

Could ΔJKL be congruent to ΔXYZ? Explain. Yes, if JL ≅ XZ. Yes, if XZ = 10. No, because the hypotenuse of one triangle is equal

in length to the leg of the other triangle. No, because the leg of one triangle is equal in length to the leg of the other triangle.

Mathematics
2 answers:
Andru [333]2 years ago
7 0
No because the hypotenuse is greater than the legs
cestrela7 [59]2 years ago
6 0

Answer: No, because the hypotenuse of one triangle is equal in length to the leg of the other triangle.

Explanation

Two triangles are congruent if their corresponding sides are congruent.

In this case one leg of the ΔXYZ measures 10 (XY=10), then its hypotenuse (the largest side in a rectangle side) must measure more than 10.

The hypotenuse of the two triangles are different: hypotenuse of  ΔJKL measures (KL=10) and the hypotenuse of  ΔXYZ measures more than 10 (YZ>10), then they are not congruent and the triangles are not congruent

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Four friends are playing a game. They randomly choose a handful of marbles from a bag. The player with the highest ratio of blue
Monica [59]

We are given the number of Blue and Purple Marbles for each of the four friends. So first we have to find the ratio of blue marbles to purple marbles for each of them.

A) Rosa

Number of blue marbles = 10

Number of purple marbles = 12

Ratio of blue to purple marbles = \frac{10}{12}=0.833

B) Chi

Number of blue marbles = 5

Number of purple marbles = 6

Ratio of blue to purple marbles = \frac{5}{6}=0.833

C) Alberto

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Ratio of blue to purple marbles = \frac{10}{6}=1.667

From the above calculations we can see that Pedro has the highest value of ratio for blue marbles to purple marbles. Also we can see Pedro is the only one for whom the number of blue marbles is more than the number of purple marbles. So this confirms that our calculation is correct.

Thus, the player which gets to go first is Pedro.

4 0
2 years ago
Read 2 more answers
Solve the following multiplication and division problems. a. 8 T. 1,398 lb. 14 oz. × 6 b. 349 lb. 6 oz. ÷ 130 c. 6 T. 294 lb. ÷
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Answer:  a) 278382 oz

b) 43 oz

c) 64.1 oz

Step-by-step explanation:

a) 8 T. 1,398 lb. 14 oz. × 6

First we need to change it in 'oz'.

As we know that

1\ ton=32000\ oz\\\\1\ lb=16\ oz

so, it becomes,

8\times 32000+1398\times 16+14\ oz\\\\=278382\ oz

8 T. 1,398 lb. 14 oz. × 6 becomes

278382\times 6\\\\=1670292\ oz

b) 349 lb. 6 oz. ÷ 130

It becomes,

349\times 16+6\ oz\\\\=5590\ oz\\\\\text{ at last it becomes}\\\\=\frac{5590}{130}\\\\=43\ oz

c) 6 T. 294 lb. ÷ 3,071

First it becomes,

6\times 32000+294\times 16\ oz\\\\=196704\ oz

At last it becomes,

\frac{196704}{3071}\\\\=64.1\ oz

Hence, a) 278382 oz

b) 43 oz

c) 64.1 oz

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Volume of cone = 1/3 x pi x r^2 x h
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