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Romashka [77]
2 years ago
10

The mass of a drop of water is about 0.025 of a gram. Which shows the mass written in scientific notation?

Mathematics
1 answer:
aleksklad [387]2 years ago
4 0
2.5E-2 or 2.5x10^-2

Hope this can help you!
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Use a normal approximation to find the probability of the indicated number of voters. In this case assume that 150 eligible vote
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The number of people who voted follows a binomial distribution with probability of having voted p=0.22 and n=150 subjects, which means the approximating normal distribution should have mean np=33 and standard deviation \sqrt{np(1-p)}\approx5.07.

With the continuity correction, you have

\mathbb P(X
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An amusement park's owners are considering extending the weeks of the year that it is opened. The owners would like to survey 10
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The best way to randomly choose the 100 families would be to allow a random number generator to come up with 100 families within a 50 radius of the amusement park.

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2 years ago
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A 92.0 kg football player at 6.50 m/s North collides with an 85.0 kg football player running at 6.00 m/s south. The 92.0 kg foot
s2008m [1.1K]

Answer:

-1.13 m/s

Step-by-step explanation:

Parameters given:

Mass of first footballer, M = 92 kg

Initial velocity of first footballer, U = 6.5 m/s (taking North to be the +ve y axis)

Mass of second footballer, m = 85 kg

Initial velocity of second footballer, u = -6.0 m/s (taking South to be the -ve y axis)

Final velocity of first footballer, V = 2.0 m/s

We need to find the final velocity of the second football (v)

Applying the principle of conservation of momentum, we have that, in a system:

Total Initial Momentum = Total Final Momentum

(M * U) + (m * u) = (M * V) + (m * v)

(92 * 6.5) + (85 * -6) = (92 * 2) + (85 * v)

598 - 510 = 184 + 85v

88 = 184 + 85v

88 - 184 = 85v

-96 = 85v

=> v = -96 / 85

v = -1.13 m/s

The final velocity of the 85 kg player is -1.13 m/s i.e 1.13 m/s South

5 0
2 years ago
A right pyramid with a square base has a base edge length of 12 meters and slant height of 6StartRoot 2 EndRoot meters. The apot
Jet001 [13]

Answer:

Volume of the right pyramid = 288 m²

Step-by-step explanation:

Volume of the pyramid = \frac{1}{3}\times {\text{Area of the rectangular base}\times height(h)

From the ΔAOB,

By Pythagoras theorem,

AB² = AO² + OB²

(6√2)² = AO² + (6)²

72 = AO² + 36

AO = √(36) = 6 m

Since base of the pyramid is a square so area of the base = (Length × Width) = (side)²

Now volume of the pyramid = \frac{1}{3}[(Length)(width)]\times height

                                               = \frac{1}{3}(12\times 12)\times 6

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Therefore, volume of the right pyramid is 288 m².

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Abdullah is a quality control expert at a factory that paints car parts. He knows that 20\ , percent of parts have an error in t
-Dominant- [34]

The error rate has decreased after changing the painting process.

<u>Step-by-step explanation:</u>

Abdulla knows that 20 percent of the parts have an error in their painting. After suggesting changes in painting process, he wants to know whether the error rate has changed.

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Number of parts that had an error=606060

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606060=x/100 \times 400400400\\=0.15%

After changing the painting process 0.15% of parts have error.

The previous percentage was 20.Hence the error rate has clearly changed.

3 0
2 years ago
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