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MariettaO [177]
2 years ago
12

A local animal feed company makes its feed by the ton, which is 2000 pounds. They want to include a medication in the feed. Each

cow needs 300 milligrams of this medication a day and each cow consumes 15 pounds of the feed per day. If there are 1000 milligrams in a gram, how many grams of the medication should the feed company add for each ton of feed they produce?
Mathematics
1 answer:
pshichka [43]2 years ago
7 0

100 milligrams for every 5 pounds

2000/5=400 doses  

400*100=40,000 milligrams= 40 grams

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For the sequence an = 2n + 1, identify the values of a0 = _____, a1 = _____, a2 = _____, and a3 = _____.
Tresset [83]

Answer:

Option A -  a_0= 2,a_1= 3,a_2= 5,a_3= 9

Step-by-step explanation:

Given : For the sequence a_n= 2^n + 1

To find : Identify the values of following?

Solution :

The nth term of the sequence is a_n= 2^n + 1

Substitute n=0,1,2 and 3

When n=0,

a_0= 2^0+ 1

a_0= 1+1

a_0=2

When n=1,

a_1= 2^1+ 1

a_1= 2+1

a_1=3

When n=2,

a_2= 2^2+ 1

a_2=4+1

a_2=5

When n=3,

a_3= 2^3+ 1

a_3= 8+ 1

a_3= 9

Therefore, The value is a_0= 2,a_1= 3,a_2= 5,a_3= 9

So, Option A is correct.

4 0
2 years ago
1. If what you gain daily continues in this manner, how much gain can you expect at the end of the week?
mamaluj [8]
1 is the answer I think
3 0
2 years ago
A brochure from the department of public safety in a northern state recommends that motorists should carry 12 items (flashlights
scoray [572]

Answer:

Mean = 6.07

Median = 7

Mode = 7

Step-by-step explanation:

Given

Data: 5\ 3\ 7\ 8\ 0\ 1\ 0\ 5\ 12\ 10\ 7\ 6\ 7\ 11\ 9

n = 15

Solving (a): The mean

Mean is calculated as:

Mean = \frac{\sum x}{n}

This gives:

Mean = \frac{5+ 3+ 7+ 8+ 0+ 1+ 0+ 5+ 12+ 10+ 7+ 6+ 7+ 11+ 9}{15}

Mean = \frac{91}{15}

Mean = 6.07

Solving (b): The median

Sort the data in ascending order:

Data: 5\ 3\ 7\ 8\ 0\ 1\ 0\ 5\ 12\ 10\ 7\ 6\ 7\ 11\ 9

Sorted: 0\ 0\ 1\ 3\ 5\ 5\  6\ 7\ 7\ 7\ 8\ 9\ 10\ 11\ 12

The median is:

Median = \frac{n + 1}{2}th

Median = \frac{15 + 1}{2}th

Median = \frac{16}{2}th

Median = 8th    

The 8th item on the sorted dataset is 7; So:

Median = 7

Solving (c): The mode

Mode = 7

Because it has a frequency of 3 (more than any other element of the dataset).

6 0
2 years ago
For the dilation, DO, K = (10, 0) → (5, 0), the scale factor is equal to _____.
eduard
Scale factor is equal to 1/2, since the point went from 10 to 5
6 0
2 years ago
Read 2 more answers
An isosceles triangle ABC with the base BC is inscribed in a circle. Find the measure of angles of it, if measure of arc BC = 10
Usimov [2.4K]

Answer:

The measures of the angles of the triangle are 51° , 64.5° , 64.5°

OR

The measures of the angles of the triangle are 129° , 25.5° , 25.5°

Step-by-step explanation:

* Lets explain the meaning of the inscribed triangle in a circle

- If a triangle inscribed in a circle, then the vertices of the triangle lie

 on the circumference of the circle and each vertex is an inscribed

 angle in the circle subtended by the opposite arc

- Fact in the circle the measure of the inscribed angle is 1/2 the

 measure of its subtended arc

* Now lets solve the problem

- Δ ABC is an isosceles with the base BC

∴ AB = AC

∴ m∠B = m∠C

- Δ ABC is inscribed in a circle

∴ ∠A is inscribed angle subtended by arc BC (minor or major)

# The measure of the minor arc is less than 180° and the measure of

  the major arc is greater then 180° and the sum of the two arcs

  equals the measure of the circle which is 360°

∴ ∠B subtended by arc AC

∴ ∠C subtended by arc AB

∵ The measure of the arc BC = 102°

- There is two cases in this question

(1) If the angle A subtended by the minor arc BC

(2) If the angle A subtended by the major arc BC

- Lets solve case (1)

∵ ∠A is an inscribed angle subtended by the minor arc BC

∴ m∠A = 1/2 the measure of the arc BC

∵ The measure of the arc BC is 102°

∴ m∠A = 1/2 × 102 = 51°

∵ The sum of the measures of the interior angles of a triangle is 180°

∴ m∠A + m∠B + m∠C = 180°

∴ 51 + m∠B + m∠C = 180° ⇒ subtract 51 from both sides

∴ m∠B + m∠C = 129°

∵ m∠B = m∠C ⇒ isosceles Δ

∴ m∠B = m∠C = 129/2 = 64.5°

* The measures of the angles of the triangle are 51° , 64.5° , 64.5°

- Lets solve case (2)

∵ ∠A is an inscribed angle subtended by the major arc BC

∴ m∠A = 1/2 the measure of the arc BC

∵ The measure of the minor arc BC is 102°

∵ The measure of the circle is 360°

∴ The measure of the major arc = 360 - 102 = 258°

∴ m∠A = 1/2 × 258 = 129°

∵ The sum of the measures of the interior angles of a triangle is 180°

∴ m∠A + m∠B + m∠C = 180°

∴ 129 + m∠B + m∠C = 180° ⇒ subtract 129 from both sides

∴ m∠B + m∠C = 51°

∵ m∠B = m∠C ⇒ isosceles Δ

∴ m∠B = m∠C = 51/2 = 25.5°

* The measures of the angles of the triangle are 129° , 25.5° , 25.5°

4 0
2 years ago
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