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2 years ago

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Victoria set a goal for the number of boxes of Girl Scout Cookies she wants to sell. So far, she has sold 33 boxes. If this is n

ine more than two-fifths of her goal, what is her goal? Could you also work it out for me?

1 answer:

WITCHER [35]2 years ago

5 0

Her goal is 60 boxes. this is all the work i did basically i set it up as an equation of looking for x and that’s my work so i hope it helps :)

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Rachel earned $ 34 $34dollar sign, 34 in 4 44 hours at her job today. She wants to know how much she could earn ( e ) (e)left pa

8090 [49]

Answer:

Rachel earn $85 in 10 hours.

Step-by-step explanation:

Rachel earned $34 in 4 hours at her job today. It means we can find his earning in 1 hour.

1 hour = $(34/4)

= $8.5

He earns $8.5 in an hour.

To find his earning in 10 hours, multiply $8.5 by 10. So,

Earning = $8.5 × 10

= $85

Hence, Rachel earn $85 in 10 hours.

8 0

2 years ago

Consider functions f and g below.

lidiya [134]

<h2>Hello!</h2>

The answer is:

The statement A "Function f is increasing, but g is decreasing."

<h2>Why?</h2>

To solve the problem and select the true statement, we need to compare both functions, using the inputs and outputs of the function "f" and the graph of the function "g" and then, discard each option.

Discarding we have:

A - Function f is increasing but g is decreasing: True.

From the shown table, we can see that the outputs of the function "f" are increasing, starting from 1.25 to 5, so, we can se that the function is increasing.

From the graph, we can see that the function "g" is the opposite of the function "f" since its outputs are decreasing, meaning that the function is decreasing.

Hence, the function "f" is increasing, but g is decreasing.

So, the statement A. "Function f is increasing, but g is decreasing." is true.

B - Both functions have positive x-intercepts.: False.

When a function intercepts the axis "x" we should be able to appreciate at least one output (y) equal to 0. We must remember that when a function intercepts the x-axis the y-value tends to 0.

Hence, the function f does not intercept the x-axis, also, we can see from the graph of the function g that there is not any x-axis intercept.

So, the statement B. "Both functions have positive x-intercepts." is not true.

C - The average rate of change of f is slower than the average rate of change of g over the interval [0, 2].: False.

From the graph of the function g, we can obtain its inputs and outputs and express it as points, and then, calculate its average of change, so, calculating we have:

$average=\frac{y_2-y_1}{x_2-x_1}$

Using the points: (0,2) and (2,5) we have:

$average=\frac{5-2}{2-0}=-0.75$

We have that the average rate of change is negative since the function is decreasing, and it's equal to 0.75.

Now, calculating the average of rate of the function f for the same interval, we have:

$average=\frac{5-2}{2-0}=1.5$

We have that the average rate of change is positive since the function is decreasing. and it's equal to 1.5

Hence, we have that the average rate of change of f is faster than the average rate of change of g over the interval [0, 2].

So, the statement C. "The average rate of change of f is slower than the average rate of change of g over the interval [0, 2]." is false.

D - The y-intercept of f is greater than the y-intercept of g: False:

When a function intercepts the y-axis, the "x" coordinate of the interception point tends to 0.

For f, we have that the y-intercept is located at "2", we can find the y-intercept using the point (0,2) where "x" is equal to 0, and "y" is equal to 2.

For g, we also have that the y-intercept is located at "2", we can find the y-intercept using the point (0,2) where "x" is equal to 0, and "y" is equal to 2.

Hence, both y-intercepts are equal.

So, the statement D. "the y-intercept of f is greater than the y-intercept of g." is false.

Therefore, we have that correct answer is:

The statement A is true.

Have a nice day!

5 0

2 years ago

Read 2 more answers

Rozonda defines the diameter of a circle as a line segment passing through the center of the circle. Is Rozonda’s definition val

larisa [96]

Answer: Yes Rozonda's definition is valid

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Miyoko's goal is to earn more than \$950$950dollar sign, 950 this week. She earns \$250$250dollar sign, 250 for every day she wo

GrogVix [38]

$250 c+ $ 180 g > $ 950

<u>Step-by-step explanation:</u>

As a cryptographer (c), Miyoko earns per day = $ 250

As a geologist (g) , Miyoko earns per day = $ 180

So the equation comes to be $250 c+ $ 180 g = $ 950

The equation can be rewritten to find c as, (950-180 g) / 250

The equation can be rewritten to find g as, (950 - 250 c) / 180

Plugin different values of c and g in the above 2 equations, we can find that ,

To achieve the goal, Miyoko requires to be a geologist for 3 days and crpytographist for 2 days.

5 0

2 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

7nadin3 [17]

The equation of the cone should be $z=\sqrt{x^2+y^2}$ . Parameterize $S$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u\,\vec k$

with $1\le u\le2$ and $0\le v\le2\pi$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=u\cos v\,\vec\imath+u\sin v\,\vec\jmath-u\,\vec k$

Then the integral of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_1^2(-u\cos v\,\vec\imath-u\sin v\,\vec\jmath+u^3\,\vec k)\cdot(u\cos v\,\vec\imath+u\sin v\,\vec\jmath-u\,\vec k)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_1^2(-u^2-u^4)\,\mathrm du\,\mathrm dv$

$=\displaystyle-2\pi\int_1^2(u^2+u^4)\,\mathrm du\,\mathrm dv=\boxed{-\frac{256\pi}{15}}$

3 0

2 years ago

Read 2 more answers