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Troyanec [42]
2 years ago
13

Ashby ate a lot for Thanksgiving dinner. He decided to go on a long run. He ran 6 miles in 57 minutes. How long did it take him

to run one mile?
Mathematics
2 answers:
juin [17]2 years ago
8 0

Rate = 57/6

This will aquire minutes per mile

Thus,

One mile = 19/2 or 9.5 minutes. :)

marshall27 [118]2 years ago
8 0

Answer : It take him to run one mile is, 9.5 minutes.

Step-by-step explanation :

As we are given that Ashby ran 6 miles in 57 minutes. Now we have to determine the time taken by him to run one mile.

As, he take time to run 6 miles distance = 57 minutes

So, he take time to run 1 miles distance = \frac{1\text{ mile}}{6\text{ mile}}\times 57\text{ minutes}

                                                                  = 9.5 minutes

Therefore, it take him to run one mile is, 9.5 minutes.

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What is the value of k such that x-5 is a factor of x3 – x2 + kx - 30?
Paraphin [41]

Answer:

k = - 14

Step-by-step explanation:

given that (x - 5) is a factor of the polynomial then x = 5 is a root and

x³ - x² + kx - 30 = 0 for x = 5, that is

5³ - 5² + 5k - 30 = 0

125 - 25 + 5k - 30 = 0

70 + 5k = 0 ( subtract 70 from both sides )

5k = - 70 ( divide both sides by 5 )

k = - 14


5 0
2 years ago
Person A is breathing five times as fast as person B. Compare the graphs of the breathing of the two people over time.
hammer [34]

Answer:

A

Step-by-step explanation:

Focus on what the question is telling you, as it's given to you in the question. It's saying five times, which means "×5" the number of person B, so it'll always be 5 times quicker, since they're breathing more times in a certain period of time than person B.

Hopefully this helped!

8 0
2 years ago
ΔEFG ~ ΔLMN. Find LM.
Vika [28.1K]
EFG ~ LMN, if EF ~ LM, then whatever the number is for EF times whatever the others are multiplied by, you will get LM
for example: 

FG (10) ~ MN (20)

if EF is (5), then LM is (10) (for you are multiplying by two.

Another example:

if FG is (100) ~ MN will be (200) (again for you are multiplying by two.

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6 0
2 years ago
Read 2 more answers
Which statements are true about circle Q? Select three options. The ratio of the measure of central angle PQR to the measure of
kkurt [141]

Answer:

<h3>- The ratio of the measure of central angle PQR to the measure of the entire circle is One-eighth. </h3><h3>- The area of the shaded sector depends on the length of the radius. </h3><h3>- The area of the shaded sector depends on the area of the circle</h3>

Step-by-step explanation:

Given central angle PQR = 45°

Total angle in a circle = 360°

Ratio of the measure of central angle PQR to the measure of the entire circle is \frac{45}{360} = \frac{1}{8}. This shows ratio that <u>the measure of central angle PQR to the measure of the entire circle is one-eighth</u>.

Area of a sector = \frac{\theta}{360}*\pi r^{2}

\theta = central angle (in degree) = 45°

r = radius of the circle = 6

Area of the sector

= \frac{45}{360}*\pi (6)^{2}\\ = \frac{1}{8}*36 \pi\\  = 4.5\pi units^{2}

<u>The ratio of the shaded sector is 4.5πunits² not 4units²</u>

From the formula, it can be seen that the ratio of the central angle to that of the circle is multiplied by area of the circle, this shows <u>that area of the shaded sector depends on the length of the radius and the area of the circle.</u>

Since Area of the circle = πr²

Area of the circle = 36πunits²

The ratio of the area of the shaded sector to the area of the circle = \frac{4.5\pi }{36 \pi } = \frac{1}{8}

For length of an arc

= \frac{45}{360}*2\pi r\\= \frac{45}{360}*2\pi (6)\\= \frac{45}{360}*12 \pi \\= \frac{12\pi }{8} \\= \frac{3\pi }{2} units

ratio of the length of the arc to the area of the circle = \frac{\frac{3\pi}{2} }{36\pi} = \frac{3}{72} =\frac{1}{24}

It is therefore seen that the ratio of the area of the shaded sector to the area of the circle IS NOT equal to the ratio of the length of the arc to the area of the circle

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The answer is letter A.
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