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2 years ago

3

Cara and her mom made turkey cookies for Thanksgiving Cara ate 3/5 of the cookies and her mom a 1/5 of the cookies how many more

cookies did car eat then her mom

2 answers:

Anna [14]2 years ago

7 0

Cara ate 2/5 more than her mom because there are 5/5 in the whole, and 3/5-1/5=2/5. Hope this helps!! :)

Vedmedyk [2.9K]2 years ago

6 0

Cara are 2 more cookies than her mom

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The number of days (X) after mailout it takes a utility company to receive payment for a customer’s bill is a normal random vari

Monica [59]

Answer:

The latest 2.5% of bills will be received in 20 more days after mail-out.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 31 days

Standard Deviation, σ = 6 days

We are given that the distribution of The number of days (X) is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

$P(X \leq x) = 0.025$

We have to find the value of x such that the probability is 0.025

$P(X \leq x) = 0.025$

$P( X \leq x) = P( z \leq \displaystyle\frac{x - 31}{6})=0.025$

Calculation the value from standard normal z table, we have,

$P( z \leq -1.960) = 0.025$

$\displaystyle\frac{x - 31}{6} = -1.960\\x = 19.24 \approx 20$

Hence, the latest 2.5% of bills will be received in 20 more days after mail-out.

4 0

2 years ago

Miguel is a golfer, and he plays on the same course each week. The following table shows the probability distribution for his sc

aivan3 [116]

1) 4.55

2) Short hit

Step-by-step explanation:

1)

The table containing the score and the relative probability of each score is:

Score 3 4 5 6 7

Probability 0.15 0.40 0.25 0.15 0.05

Here we call

X = Miguel's score on the Water Hole

The expected value of a certain variable X is given by:

$E(X)=\sum x_i p_i$

where

$x_i$ are all the possible values that the variable X can take

$p_i$ is the probability that $X=x_i$

Therefore in this problem, the expected value of MIguel's score is given by:

$E(X)=3\cdot 0.15 + 4\cdot 0.40 + 5\cdot 0.25 + 6\cdot 0.15 + 7\cdot 0.05=4.55$

2)

In this problem, we call:

X = Miguel's score on the Water Hole

Here we have that:

- If the long hit is successfull, the expected value of X is

$E(X)=4.2$

- Instead, if the long hit fails, the expected value of X is

$E(X)=5.4$

Here we also know that the probability of a successfull long hit is

$p(L)=0.4$

Which means that the probabilty of an unsuccessfull long hit is

$p(L^c)=1-p(L)=1-0.4=0.6$

Therefore, the expected value of X if Miguel chooses the long hit approach is:

$E(X)=p(L)\cdot 4.2 + p(L^C)\cdot 5.4 = 0.4\cdot 4.2 + 0.6\cdot 5.4 =4.92$

In part 1) of the problem, we saw that the expected value for the short hit was instead

$E(X)=4.55$

Since the expected value for X is lower (=better) for the short hit approach, we can say that the short hit approach is better.

8 0

2 years ago

Find three different irrational numbers between 0.13 and 0.14

tino4ka555 [31]

Answer:0.13468995325789542.....

0.135789075421345688....

0.136800865431234668...

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A scientist studying water quality measures the lead level in parts per billion (ppb) at each of 49 randomly chosen locations al

NeX [460]

Complete Question

The complete qustion is shown on the first uploaded image

Answer:

The correct option is B

Step-by-step explanation:

From the question we are told that

The sample size is $n = 49$

The mean is $\mu = 17ppb$

The standard deviation is $\sigma = 14 ppb$

Generally the standard error of this measurement is mathematically represented as

$\sigma_z = \frac{\sigma}{\sqrt{n} }$

substituting values

$\sigma_{\= x} = \frac{14}{\sqrt{49} }$

$\sigma_{\= x} = 2$ ppb

Now the probability that the mean lead level from the sample of 49 measurements T is less than 15 ppb represented as P(X < 15 )

Next is to find the z value

$z = \frac{\mu -\sigma }{\sigma_{\= x}}$

$z = \frac{15-17}{2}$

$z = -1$

Now checking the z-table for the z-score of -1 we have

$P(X$

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2 years ago

Trevor is training for a race he swims 1/2 lap in 4/5 minute at that race how many minutes does it take for Trevor to swim each

Korvikt [17]

8/5 minutes. Is the answer

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2 years ago