The peso is the currency of Mexico. On October 17, 2016, the exchange rate for 1 Mexican peso was $0.053 U.S. If a traveler exch
2 answers:
Answer:
7547 Mexican pesos
Step-by-step explanation:
The exchange rate for 1 Mexican peso was $0.053
A traveler exchanged $400 (U.S.) for Mexican pesos.
Let the Mexican pesos exchanged for $400 be x
0.053 U.S. Dollars = 1 Mexican pesos
400 U.S. Dollar = 0.053x Mexican pesos
= x
x = 7547.169 ≈ 7547 Mexican pesos
They received 7547 Mexican pesos
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Answer:
at x = 10,
Step-by-step explanation:
The given equation is
Here, lets substitute the value of x = 10
So, the equation simplifies to ,
= (4 x 100) + 170 + 2 = 400 + 170 + 2
= 572
So, at x = 10,
Answer:
1627190
Step-by-step explanation:
(see attached for reference)
Given the number 1627187, we can see that the number in the tens place is the number 8.
How we round this depends on the number immediately to the right of this number. (i.e the digit in the ones place)
Case 1: If the digit in the ones place is less less than 5, then the number in the tens place remains the same and replace all the digits to its right with zeros
Case 2: If the digit in the ones places is 5 or greater, then we increase the digit in the tens place and replace all the digits to its right with zeros.
In our case, the digit in the ones places is 7, this greater than 5, hence according to Case 2 above, we increase the digit in the tens place by one (from 8 to 9) and replace all the digits to its right by zeros giving us:
1627190
F(x) = 4x - 1
g(x) = 2x² + 3
1. (f + g)(x) = (4x - 1) + (2x² + 3)
(f + g)(x) = 2x² + 4x + (-1 + 3)
(f + g)(x) = 2x² + 4x + 2
Domain: {x| -∞ < x < ∞}, (-∞, ∞)
2. (f - g)(x) = (4x + 1) - (2x² + 3)
(f - g)(x) = 4x + 1 - 2x² - 3
(f - g)(x) = -2x² + 4x + 1 - 3
(f - g)(x) = -2x² + 4x - 2
Domain: {x|-∞ < x < ∞}, (-∞, ∞)
3. (g - f)(x) = (2x² + 3) - (4x - 1)
(g - f)(x) = 2x² + 3 - 4x + 1
(g - f)(x) = 2x² - 4x + 3 + 1
(g - f)(x) = 2x² - 4x + 4
Domain: {x| -∞ < x < ∞}, (-∞, ∞)
4. (f · g)(x) = (4x + 1)(2x² + 3)
(f · g)(x) = 4x(2x² + 3) + 1(2x² + 3)
(f · g)(x) = 4x(2x²) + 4x(3) + 1(2x²) + 1(3)
(f · g)(x) = 8x³ + 12x + 2x² + 3
(f · g)(x) = 8x³ + 2x² + 12x + 3
Domain: {x| -∞ < x < ∞}, (-∞, ∞)
5.
Domain: 2x² + 3 ≠ 0
- 3 - 3
2x² ≠ 0
2 2
x² ≠ 0
x ≠ 0
(-∞, 0) ∨ (0, ∞)
6.
Domain: 4x - 1 ≠ 0
+ 1 + 1
4x ≠ 0
4 4
x ≠ 0
(-∞, 0) ∨ (0, ∞)
g(x) = 2x² + 3
1. (f + g)(x) = (4x - 1) + (2x² + 3)
(f + g)(x) = 2x² + 4x + (-1 + 3)
(f + g)(x) = 2x² + 4x + 2
Domain: {x| -∞ < x < ∞}, (-∞, ∞)
2. (f - g)(x) = (4x + 1) - (2x² + 3)
(f - g)(x) = 4x + 1 - 2x² - 3
(f - g)(x) = -2x² + 4x + 1 - 3
(f - g)(x) = -2x² + 4x - 2
Domain: {x|-∞ < x < ∞}, (-∞, ∞)
3. (g - f)(x) = (2x² + 3) - (4x - 1)
(g - f)(x) = 2x² + 3 - 4x + 1
(g - f)(x) = 2x² - 4x + 3 + 1
(g - f)(x) = 2x² - 4x + 4
Domain: {x| -∞ < x < ∞}, (-∞, ∞)
4. (f · g)(x) = (4x + 1)(2x² + 3)
(f · g)(x) = 4x(2x² + 3) + 1(2x² + 3)
(f · g)(x) = 4x(2x²) + 4x(3) + 1(2x²) + 1(3)
(f · g)(x) = 8x³ + 12x + 2x² + 3
(f · g)(x) = 8x³ + 2x² + 12x + 3
Domain: {x| -∞ < x < ∞}, (-∞, ∞)
5.
Domain: 2x² + 3 ≠ 0
- 3 - 3
2x² ≠ 0
2 2
x² ≠ 0
x ≠ 0
(-∞, 0) ∨ (0, ∞)
6.
Domain: 4x - 1 ≠ 0
+ 1 + 1
4x ≠ 0
4 4
x ≠ 0
(-∞, 0) ∨ (0, ∞)