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Gala2k [10]
2 years ago
6

For every 1 litre of water used to make a medicine, 300 ml of sucrose and 750ml of saline solution are used. Express the amount

of water, sucrose and saline solution needed as a ratio in its simplest form.
Mathematics
1 answer:
Neko [114]2 years ago
8 0

Answer: Required ratio will be 20:6:15.

Step-by-step explanation:

Since we have given that

For every 1 liter of water used to make a medicine, 300 ml of sucrose and 750 ml of saline solution are used.

So, We need to express the amount of water, sucrose and saline solution in its simplest form.

So, all amount will be in same units i.e. ml.

As we know that

1\ liter=1000\ milimeter\\

So, Ratio will be expressed as

\text{Amount of water : Sucrose : saline solution}\\\\=1000:300:750\\\\=200:60:150\\\\=40:12:30\\\\=20:6:15

Hence, required ratio will be 20:6:15.

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When a number is decreased by 8.5%, the result is 33. What is the original number to the nearest tenth?
Reil [10]

Answer:

Step-by-step explanation:

Let the original number be x

(100-8.5)% of x = 33

91.5% of x = 33

\frac{91.5}{100}x=33\\\\x=33*\frac{100}{91.5}\\\\x=36.07

x= 36.1

7 0
2 years ago
At the beginning of year 1, Zack invests $700 at an annual compound interest
REY [17]

Answer: the answer is C

Step-by-step explanation:

8 0
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Read 2 more answers
Two standardized​ tests, a and​ b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×
Romashka [77]

Answer:

(a) The mean score of test A is 1210.

(b) The mean score of test A is 1210.

(c) The standard deviation of  test A is 80.

(d) The value of Q₃ for test A is 1170.

(e) The value of median for test A is 1090.

(f) The value of IQR for test A is 290.

Step-by-step explanation:

The relation between two standardized tests <em>A</em> and <em>B</em> is:

50A=40B+50

The equation above approximates the relationship between scores on the two tests.

The summary statistics for test B are as follows:

Lowest Score = 21

Mean score = 29

Standard deviation = 2

Q₃ = 28

Median = 26

IQR = 6

(a)

Compute the lowest score on test A as follows:

A=40B+50\\=(40\times21)+50\\=890

Thus, the lowest score on test A is 890.

(b)

Compute the mean score of test A as follows:

<h2>A=40B+50\\=(40\times29)+50\\=1210</h2>

Thus, the mean score of test A is 1210.

(c)

Compute the mean score standard deviation of test A as follows:

<h2>A=40B+50\\=(40\times2)\\=80</h2>

Thus, the standard deviation of  test A is 80.

(d)

Compute the value of Q₃ for test A as follows:

A=40B+50\\=(40\times28)+50\\=1170

Thus, the value of Q₃ for test A is 1170.

(e)

Compute the value of median for test A as follows:

A=40B+50\\=(40\times26)+50\\=1090

Thus, the value of median for test A is 1090.

(f)

Compute the value of IQR for test A as follows:

A=40B+50\\=(40\times6)+50\\=290

Thus, the value of IQR for test A is 290.

6 0
2 years ago
When it was 70 degrees outside, 50 members showed up at a beach club. For each degree the temperature rose, another 10 members c
strojnjashka [21]

The function f(t), that represents the number of members at the beach club as a function of the temperature is f(t) = 10t + 50

<u>Solution:</u>

Given that, When it was 70 degrees outside, 50 members showed up at a beach club.  

For each degree the temperature rose, another 10 members came to the beach club.  

We have to write the function, f(t), that represents the number of members at the beach club as a function of the temperature.

Now, according to the given information,  

Initially 50 members and then, members keep on adding by rise in temperature,

So, 50 + t x 10  [ t represents change in temperature, and 10 is number of people who joins club ]

Then, f(t) = 10t + 50.

Hence, the function is f(t) = 10t + 50

3 0
2 years ago
∆ABC is isosceles, AB = BC, and CH is an altitude. How long is AC, if CH = 84 cm and m∠HBC = m∠BAC +m∠BCH?
son4ous [18]
I think I could help you
Have fun and feel free to ask me something new.
Or we can prove some properities without calculating by details

3 0
2 years ago
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