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Which expression is the result of solving the equation ax - b = cy for 2? (For a + 0)

Masja [62]

I would say cy hopes this help

6 0

2 years ago

the performance score of 10 adults is recorded, and the results are 83 87 90 92 93 100 104 111 115 121 find the standard deviati

luda_lava [24]

Answer:

The standard deviation of the data set is $\sigma = 12.7906$ .

Step-by-step explanation:

The Standard Deviation is a measure of how spread out numbers are. Its symbol is σ (the greek letter sigma)

To find the standard deviation of the following data set

$\begin{array}{cccccccc}83&87&90&92&93&100&104&111\\115&121&&&&&&\end{array}$

we use the following formula

$\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{X}\right)^2 }}{n-1} }$

Step 1: Find the mean $\left( \overline{X} \right)$ .

The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:

$Mean = \frac{Sum ~ of ~ terms}{Number ~ of ~ terms}$

$Mean = \frac{Sum ~ of ~ terms}{Number ~ of ~ terms}=\frac{83+87+90+92+93+100+104+111+115+121}{10} \\\\Mean = \frac{996}{10} =\frac{498}{5}=99.6$

Step 2: Create the below table.

Step 3: Find the sum of numbers in the last column to get.

$\sum{\left(x_i - \overline{X}\right)^2} = 1472.4$

Step 4: Calculate σ using the above formula.

$\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{X}\right)^2 }}{n-1} } = \sqrt{ \frac{ 1472.4 }{ 10 - 1} } \approx 12.7906$

3 0

2 years ago

Mattel Corporation produces a remote-controlled car that requires three AA batteries. The mean life of these batteries in this p

goldfiish [28.3K]

Answer:

0.0406, 0.8284,0.7887

Step-by-step explanation:

Given that Mattel Corporation produces a remote-controlled car that requires three AA batteries

X is N(34, 5.5)

Hence sample size of 25 would follow a t distribution with df = 24

This is because sample size <30

t distribution with df 24 would be bell shaped symmetrical about the mean and unimodal.

Std error of sample mean = std dev /sqrt n= $\frac{5.5}{5} \\=1.1$

Prob (X>36) = $P(t>\frac{36-34}{1.1} ) = P(t>1.82)\\= 0.04063$

i.e nearly 4.1% of the sample would have a mean useful life of more than 36 hours

X>33.5 implies $t>-0.45$

=0.82837

=0.8284 proportion will have a mean useful life greater than 33.5 hours

Proportion between 33.5 and 36 hours

= $0.3284+0.4593=0.7887$

6 0

2 years ago

A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance tra

alina1380 [7]

Answer:

1.734

Step-by-step explanation:

Given that:

A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles).

The fitted regression is Time = −7.126 + .0214 Distance

Based on a sample size n = 20

And an Estimated standard error of the slope = 0.0053

the critical value for a right-tailed test to see if the slope is positive, using ∝ = 0.05 can be computed as follows:

Let's determine the degree of freedom df = n - 1

the degree of freedom df = 20 - 2

the degree of freedom df = 18

At the level of significance ∝ = 0.05 and degree of freedom df = 18

For a right tailed test t, the critical value from the t table is :

$t_{0.05, 18} =$ 1.734

5 0

2 years ago

What is the product? (-2x-9y^2)(-4x-3)

telo118 [61]

Answer:-8x^2-6x+36xy^2+27y^2

Step-by-step explanation:

using the FOIL method

6 0

2 years ago

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