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Oxana [17]
2 years ago
4

Meryl needs to cut down 10.5 trees for every 5 cabins she builds. How many trees will she need to cut down if she builds 3 cabin

s?
Mathematics
1 answer:
Rashid [163]2 years ago
5 0

Answer:

6.3 trees.

Step-by-step explanation:

We have been given that Meryl needs to cut down 10.5 trees for every 5 cabins she builds.

Let us find the number of trees Meryl needs to cut down to build 1 cabin by dividing 10.5 by 5.

\text{Number of tress needed to build 1 cabin}=\frac{10.5}{5}

\text{Number of tress needed to build 1 cabin}=2.1

Now let us multiply 2.1 by 3 to find the number of trees Meryl needs to cut down to build 3 cabins.

\text{Number of tress needed to build 3 cabins}=2.1\times 3

\text{Number of tress needed to build 3 cabins}=6.3

Therefore, Meryl needs to cut down 6.3 trees, if she builds 3 cabins.

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EXAMPLE 5 If F(x, y, z) = 4y2i + (8xy + 4e4z)j + 16ye4zk, find a function f such that ∇f = F. SOLUTION If there is such a functi
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If there is such a scalar function <em>f</em>, then

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Differentiate both sides with respect to <em>y</em> :

\dfrac{\partial f}{\partial y}=8xy+4e^{4z}=8xy+\dfrac{\partial g}{\partial y}

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Integrate both sides with respect to <em>y</em> :

g(y,z)=4ye^{4z}+h(z)

Plug this into the equation above with <em>f</em> , then differentiate both sides with respect to <em>z</em> :

f(x,y,z)=4xy^2+4ye^{4z}+h(z)

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Question 14. A carousel makes one complete revolution every 75 seconds. Levi sits on the carousel 4 feet from its center. If the
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Answer:

The correct option is;

H. 32·π

Step-by-step explanation:

The given information are;

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The time length of a carousel ride = 5 minutes

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A wild animal generally stays at least x mi from the edge of a forest. For a rectangular forest preserve that is 2 mi
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Answer:

Area = 4x^2 - 14x + 10

Step-by-step explanation:

<em>See Attachment for Complete Question</em>

Given

Width = 5mi --- For the forest

Length = 2mi -- --- For the forest

Required

Determine the area of the habitat

Since the distance between the animal's habitat is x mi on both sides;

The length and width of the habitat is:

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Width = 5 - 2x

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Expand

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Open Brackets

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Area = 10 - 14x + 4x^2

Reorder

Area = 4x^2 - 14x + 10

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Area = 4x^2 - 14x + 10

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