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Strike441 [17]
2 years ago
12

What is the perimeter of a triangle with vertices located at (-1, 4), (2, 7), and (1, 5), rounded to the nearest hundredth? A. 7

.63 units B. 7.89 units C. 8.71 units D. 9.24 units
Mathematics
2 answers:
svp [43]2 years ago
6 0

Answer: C

apex

Step-by-step explanation:

Pavel [41]2 years ago
5 0
We are given with the points (-1,4), (2,7) and (1,5) as the sides of the triangle. The area of the triangle can be determined by determining first the length of the sides. Via distance formula, the sides are 3 sqrt 2, sqrt 5 and sqrt 5. The perimeter thus is equal to 8.71 units
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18 buckets would be the answer.


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Which shows the factored form of x2 – 12x – 45?
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Hi!

(x+a)·(x+b) = x²+xa+xb+ab = x²-12x-45

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2 years ago
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Point b has coordinates (3,-4) and lies on the circle whose equation is x^2 + y^2= 25. If angle is drawn in a standard position
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<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
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Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
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2 years ago
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ddd [48]

Answer:

1

Step-by-step explanation:

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