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2 years ago

PLEASE HELP

Mathematics

2 answers:

konstantin123 [22]2 years ago

7 0

The length of the minor arc AB is 6.3cm

kipiarov [429]2 years ago

3 0

Answer:

D. 6.3 cm

Step-by-step explanation:

First we find the circumference of the circle. The formula for circumference is

C = 2πr

Using 3.14 for π and our value for 5, we have

C = 2(3.14)(5) = 31.4 cm

Next we find the portion of the circle represented by this sector. The angle is 72 out of 360 total degrees:

72/360 = 36/180 = 6/30 = 1/5

Multiply the circumference by this fraction:

1/5(31.4) = 6.28 ≈ 6.3 cm

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A tire manufacturer has a 60,000 mile warranty for tread life. The company wants to make sure the average tire lasts longer than

aleksandrvk [35]

Answer:

The alternative hypothesis being tested in this example is that the tire life is of more than 60,000 miles, that is:

$H_1: \mu > 60,000$

Step-by-step explanation:

A tire manufacturer has a 60,000 mile warranty for tread life. The company wants to make sure the average tire lasts longer than 60,000 miles.

At the null hypothesis, we test if the tire life is of at most 60,000 miles, that is:

$H_0: \mu \leq 60,000$

At the alternative hypothesis, we test if the tire life is of more than 60,000 miles, that is:

$H_1: \mu > 60,000$

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2 years ago

The quotient of 36 and 3 is j. write expression

Dovator [93]

This might be a mistake but i'll give it a go:

36/3 = j

4 0

2 years ago

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Find the measures of the three angles, in radians, of the triangle with the given vertices: d(1,1,1), e(1,−5,2), and f(−2,2,7).

Oduvanchick [21]

Consider triangle DEF with vertices D(1,1,1), E(1,-5,2) and F(-2,2,7).

1. Find

$\overrightarrow{DE}=(1-1,-5-1,2-1)=(0,-6,1),\\ \\\overrightarrow{DF}=(-2-1,2-1,7-1)=(-3,1,6).$

Then

$\cos \angle D=\dfrac{0\cdot (-3)+(-6)\cdot 1+1\cdot 6}{\sqrt{0^2+(-6)^2+1^2}\cdot \sqrt{(-3)^2+1^2+6^2}}=\dfrac{0}{\sqrt{37} \cdot \sqrt{46} }=0.$

2. Find

$\overrightarrow{ED}=(1-1,1-(-5),1-2)=(0,6,-1),\\ \\\overrightarrow{EF}=(-2-1,2-(-5),7-2)=(-3,7,5).$

Then

$\cos \angle E=\dfrac{0\cdot (-2)+6\cdot 7+(-1)\cdot 5}{\sqrt{0^2+6^2+(-1)^2}\cdot \sqrt{(-3)^2+7^2+5^2}}=\dfrac{37}{\sqrt{37} \cdot \sqrt{83} }=\sqrt{\dfrac{37}{83}}.$

3. Find

$\overrightarrow{FE}=(1-(-2),-5-2,2-7)=(3,-7,-5),\\ \\\overrightarrow{FD}=(1-(-2),1-2,1-7)=(3,-1,-6).$

Then

$\cos \angle F=\dfrac{3\cdot 3+(-7)\cdot (-1)+(-5)\cdot (-6)}{\sqrt{3^2+(-7)^2+(-5)^2}\cdot \sqrt{3^2+(-1)^2+(-6)^2}}=\dfrac{46}{\sqrt{83} \cdot \sqrt{46} }=\sqrt{\dfrac{46}{83}}.$

$\angle E=\arccos0=\dfrac{\pi}{2},\\ \\
\angle D=\arccos\letf(\sqrt{\dfrac{37}{83}}\right)\approx 0.27\pi,\\ \\
\angle F=\arccos\letf(\sqrt{\dfrac{46}{83}}\right)\approx 0.23\pi.$

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1 year ago

In 2011, the world's largest pumpkin weighed 825 kilograms. An average-sized pumpkin weighs 5,000 grams. The 2011 world-record p

zzz [600]

1000 g = 1 kg
5,000 g = 5 kg
825 kg - 5 kg = 820 kg

<span>The 2011 world-record pumpkin weighs __820 kg___ kilograms more than an average-sized pumpkin. </span>

6 0

2 years ago

Mandy works construction. Shes knows that a 5 meter long metal bar has a mass of 40 kg.Mandy wants to figure out the mass (w) of

Agata [3.3K]

Answer:

24 kg

Step-by-step explanation:

40/5 = 8 and 3x8 = 24

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2 years ago

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