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horsena [70]
2 years ago
6

In the cathode ray tube experiment, J. J. Thomson passed an electric current through different gases inside a cathode ray tube i

n the presence of an electric field. In which two ways did this experiment change scientists’ understanding of the atom? A- It showed that atoms combine in different proportions. B-It showed that atoms can be divided into smaller parts.C- It showed that all atoms of the same element are similar. D-It showed that individual atoms could be destroyed. It showed that all atoms contain electrons.
Chemistry
2 answers:
omeli [17]2 years ago
6 0

The answer is: B-It showed that atoms can be divided into smaller parts.

It showed that all atoms contain electrons.

Tomson concluded that atoms are divisible and that the corpuscles are their building blocks (atoms are made up of smaller particles).

J. J. Thomson discovered the electron in 1897.

His "plum pudding" model (1904) suggested: the electrons are embedded in the positive charge.

With this model, he abandoned his earlier hypothesis (the atom was composed of immaterial vortices).  

lara31 [8.8K]2 years ago
6 0
It showed that all atoms contain electrons
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What is the percent yield of this reaction if 22.o g of Mgl2 is produced by the reaction of 25.0 g of Mg with 25.0 g of l2?
expeople1 [14]

% yield = 80.719

<h3>Further explanation</h3>

Given

22.0 g of Mgl₂

25.0 g of Mg

25.0 g of l₂

Required

The percent yield

Solution

Reaction

Mg + I₂⇒ MgI₂

mol Mg = 25 g : 24.305 g/mol = 1.029

mol I₂ = 25 g : 253.809 g/mol = 0.098

Limiting reactant = I₂

Excess reactant = Mg

mol MgI₂ based on I₂, so mol MgI₂ = 0.098

Mass MgI₂ (theoretical):

= mol x MW

= 0.098 x 278.114

= 27.255 g

% yield = (actual/theoretical) x 100%

% yield = (22 / 27.255) x 100%

% yield = 80.719

8 0
1 year ago
22. How many atoms are there in 344.75 g of gold nugget? a. 1.05 x 10 to the power of 24 atoms b. 1.05 x 10 to the power of 23 a
mixas84 [53]

Answer:

1.053×10²⁴ atoms of gold

Explanation:

Hello,

Gold nugget are usually the natural occurring gold and they contain 85% - 90% weight of pure gold.

In this question, we're required to find the number of atoms in 344.75g of a gold nugget.

We can use mole concept relationship between Avogadro's number and molar mass.

1 mole = molar mass

Molar mass of gold = 197 g/mol

1 mole = Avogadro's number = 6.022 × 10²³ atoms

Number of mole = mass / molar mass

Mass = number of mole × molar mass

Mass = 1 × 197

Mass = 197g

197g is present in 6.022×10²³ atoms

344.75g will contain x atoms

x = (344.75 × 6.022×10²³) / 197

X = 1.053×10²⁴ atoms

Therefore 344.75g of gold nugget will contain 1.053×10²⁴ atoms of gold

5 0
2 years ago
The combustion of propane is best described as an
GalinKa [24]
<h3><u>Answer;</u></h3>

Exothermic chemical reaction

<h3><u>Explanation;</u></h3>
  • Exothermic reactions are chemical reactions where the products have less energy that the reactants.
  • Exothermic reactions give off energy, usually in the form of heat, while endothermic reactions absorb energy.
  • The combustion of propane is definitely an exothermic reaction because it generates a lot of heat.

5 0
2 years ago
Element z reacts with bromine to form an ionic compound zbr2. A) state with reasons i) the physical properties of zbr2 at room t
kondor19780726 [428]

Answer:

The answer to your question is:

Explanation:

A) state with reasons

From the description we can conclude that the compound is a binary salt. Binary salts are form by a metal and a non metal, one of their characteristics is that the elements are attached by an ionic bond.

i) the physical properties of ZBr2 at room temperature

Crystals, high fusion and boiling points, they conduct water when dissolved in water, they are soluble in water but not in gasoline.

ii) whether z is a metal or non metal.

Z is a metal

3 0
2 years ago
If a car travels 1255 miles how many kilometers is that i mile = 1.609km
ANTONII [103]

Answer:

2,019 km

Explanation:

Step 1: Given data

Distance traveled by the car (D): 1,255 mi

Step 2: Convert the distance traveled by the car to kilometers

To convert one unit into another, we use a conversion factor. In this case, the appropriate conversion factor between miles and kilometers is 1 mile = 1.609 km. The distance traveled by the car, in kilometers, is:

D = 1,255 mi × (1.609 km/1 mi) = 2,019 km

3 0
2 years ago
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