Answer:
it's 55
Step-by-step explanation:
Plz mark as brainliest and follow me plz
X*y = 450
y = 1/2x
x(1/2x) = 450
1/2x^2 = 450
x^2 = 450 * 2
x^2 = 900
x = sqrt 900
x = 30
y = 1/2(30)
y = 15
so ur numbers are : x = 30 and y = 15...but I am not sure of ur answer choices.
Answer:
Given: A triangle ABC and a line DE parallel to BC.
To prove: A line parallel to one side of a triangle divides the other two sides proportionally.
Proof: Consider ΔABC and DE be the line parallel to Bc, then from ΔABC and ΔADE, we have
∠A=∠A (Common)
∠ADE=∠ABC (Corresponding angles)
Thus, by AA similarity, ΔABC is similar to ΔADE, therefore
AB/AD= AC/AE
⇒AD+DB/AD = AE+EC/AE
⇒1+DB/AD = 1+ EC/AE
⇒DB/AD = EC/AE
Therefore, a line parallel to one side of a triangle divides the other two sides proportionally.
⇒Therefore Proved
Hope this helps!!!
<span>A geometric sequence is a sequence of
numbers where each term after the first is found by multiplying the
previous one by a fixed, non-zero number called the common ratio.
</span>The common ration is obtained by dividing the a term by the preceding term.
Given that f<span>our
students wrote sequences during math class with
Andre writing

Brenda
writing </span>
Camille writing
Doug writing

Notice that the common ratio for the four students is

.
For Andre, the last term is wrong and hence his sequence is not a geometric sequence.
For Brenda, the last term is wrong and hence her sequence is not a geometric sequence.
For Camille, her sequence is not a geometric sequence.
For Doug, his sequence is a geometric sequence with a common ratio of

.
Therefore, Doug wrote a geometric sequence.
You need to solve for one variable in equation 1 and substitute it in equation 2 to solve.
Equation 1: x+y=24
x= number of 3 pt questions
y= number of 5 pt questions
24= Total number of questions
Equation 2: 3x+5y=100
100= Total point value possible on test
3x= point value of 3 pt questions
5y= point value of 5 pt questions
x+y=24
Subtract y from both sides
x=24-y
Substitute in equation 2:
3x+5y=100
3(24-y) +5y=100
72-3y+5y=100
72+2y=100
Subtract 72 from both sides
2y=28
Divide both sides by 2
y=14
Substitute y=14 back in to solve for x:
3x+5y=100
3x+5(14)=100
3x+70=100
Subtract 70 from both sides
3x=30
Divide both sides by 3
x=10
So there are 10 three point questions
There are 14 five point questions.
Hope this helped! :)