Answer:
18.67% of bills are greater than $131
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What proportion of bills are greater than $131
This proportion is 1 subtracted by the pvalue of Z when X = 131. So



has a pvalue of 0.8133
1 - 0.8133 = 0.1867
18.67% of bills are greater than $131
Answer:
4
Step-by-step explanation:
Given that :
Clients are interviewed in groups of 2 on the first day; meaning two persons at a time
Second day, clients are interviewed in groups of 4; meaning 4 persons at a time.
Therefore, if the same number of clients are to be interviewed on each day, the smallest number of clients that could be interviewed each day could be obtained by getting the Least Common Multiple of both numbers: 2 and 4
- - - - 2 - - - 4
2 - - - 1 - - - 2
2 - - - 1 - - - 1
Therefore, the Least common multiple is (2 * 2) = 4
Therefore, the smallest number of clients that could be interviewed each day is 4.
The tension in the string balances out, and thus equals the centripetal force of the ball
T = mv^2/r
<span>
if it only takes half the time to finish one orbit it has to be moving at twice the original speed. </span>
<span>
And since v is squared T will increase by 4 </span>
<span>
T' = m(2v)^2/r </span>
<span>
T' = 4mv^/r = 4T </span>
<span>
T' = 24.0 N
I hope my answer has come to your help. Have a nice day ahead and may God bless you always!
</span>
Answer:
1627190
Step-by-step explanation:
(see attached for reference)
Given the number 1627187, we can see that the number in the tens place is the number 8.
How we round this depends on the number immediately to the right of this number. (i.e the digit in the ones place)
Case 1: If the digit in the ones place is less less than 5, then the number in the tens place remains the same and replace all the digits to its right with zeros
Case 2: If the digit in the ones places is 5 or greater, then we increase the digit in the tens place and replace all the digits to its right with zeros.
In our case, the digit in the ones places is 7, this greater than 5, hence according to Case 2 above, we increase the digit in the tens place by one (from 8 to 9) and replace all the digits to its right by zeros giving us:
1627190