Question

when joe bowls he can get a strike 60% of the time, what is the probability jow will get at least 3 strikes out of 4 tries?

Answer 1

Answer:

34.56%

Step-by-step explanation:

This is a binomial probability that can easily be solved using the formula:

$p(x)=\frac{n!}{x!(n-x)!}*p^xq^{n-x}$

Where

• n is the total number of trials (here it is 4)
• x is the number of "success" ( here it is 3)
• p is the success rate (given as 60%=0.6)
• q is the not success rate ( it is 1 - p, so 0.4)

Substituting these values into the formula gives us our answer:

$p(x)=\frac{n!}{x!(n-x)!}*p^xq^{n-x}\\p(x)=\frac{4!}{3!(4-3)!}*(0.6)^{3}(0.4)^{4-3}\\p(x)=\frac{4!}{3!1!}*(0.6)^{3}(0.4)^{1}\\p(x)=0.3456$

In percentage, the probability is 34.56%