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Tatiana [17]
2 years ago
9

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Line m has no y

-intercept, and its x-intercept is (3, 0). Line n has no x-intercept, and its y-intercept is (0, -4). The equation of line m is 3 , and the equation of line n is -4 .
Mathematics
1 answer:
Kobotan [32]2 years ago
7 0

Answer:

Part A) The equation of the line m is x=3

Part B) The equation of the line n is y=-4

Step-by-step explanation:

Part A) Line m has no y-intercept, and its x-intercept is (3, 0)

we know that

If a line has no y-intercept , then is a vertical line (parallel to the y-axis)

the equation of the line m is equal to the x-coordinate of the x-intercept

so

x=3

Part B) Line n has no x-intercept, and its y-intercept is (0, -4)

we know that

If a line has no x-intercept , then is a horizontal line (parallel to the x-axis)

the equation of the line n is equal to the y-coordinate of the y-intercept

so

y=-4

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7nadin3 [17]

Answer:

The distance between the two playing pieces is of 6.4 units.

Step-by-step explanation:

Suppose we have two points:

A = (x_{1}, y_{1})

B = (x_{2}, y_{2})

The distance between these points is:

D = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}

Distance between:

A(-2,3) and B(3,-1)

D = \sqrt{(3 - (-2))^{2} + (-1 - 3)^{2}} = \sqrt{41} = 6.4

The distance between the two playing pieces is of 6.4 units.

5 0
2 years ago
The equation r = 6t gives the number of albums released, r, by a record label over time in years, t. If you graph this relations
GalinKa [24]
R = 6t.....subbing in (8,48).....t = 8 and r = 48
48 = 6(8)
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5 0
2 years ago
Read 2 more answers
A cell phone company is looking to place a new tower to service 3 cities. In order for it to best service each city, it needs to
omeli [17]

Answer:

  • circumscribed circle
  • The center of a circle circumscribing the triangle connecting the 3 cities will be equidistant from all three cities.

Step-by-step explanation:

The circumscribed circle or <em>circumcircle</em> of a polygon is a circle that passes through all the vertices of the polygon. The center of the circle, the circumcenter, is equidistant from all of the polygon's vertices.

The center is found at the point of intersection between the perpendicular bisectors of any two (non-parallel) chords of the circle. That is, <em>the perpendicular bisectors of any two of the sides of the triangle joining the cities will intersect at the circumcenter</em>.

The method of locating the center of the circle this way is simple and effective.

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2 years ago
General solution of equation sin x + sin 5x = sin 2x + sin 4x is
zaharov [31]

Answer:

x=nπ3, n∈I

Step-by-step explanation:

sin x + sin 5x = sin 2x + sin 4x

⇒⇒   2 sin 3x cos 2x = 2 sin 3x cos x

⇒⇒   2 sin 3x(cos 2x - cos x) = 0

⇒    sin 3x=0 ⇒ 3x=nπ ⇒ x=nπ3⇒    sin 3x=0 ⇒ 3x=nπ ⇒ x=nπ3 , n∈I, n∈I

or    cos 2x−cos x=0 ⇒ cos 2x=cos xcos 2x-cos x=0 ⇒ cos 2x=cos x

⇒   2x=2nπ±x  ⇒  x=2nπ, 2nπ3⇒   2x=2nπ±x  ⇒  x=2nπ, 2nπ3 , n∈I, n∈I

But solutions obtained by x=2nπx=2nπ , n∈I, n∈I or x=2nπ3x=2nπ3 , n∈I, n∈I are all involved in x=nπ3x=nπ3 , n∈I

7 0
2 years ago
let x = the amoun of raw sugar in tons a procesing plant is a sugar refinery process in one day . suppose x can be model as expo
anygoal [31]

Answer:

The answer is below

Step-by-step explanation:

A sugar refinery has three processing plants, all receiving raw sugar in bulk. The amount of raw sugar (in tons) that one plant can process in one day can be modelled using an exponential distribution with mean of 4 tons for each of three plants. If each plant operates independently,a.Find the probability that any given plant processes more than 5 tons of raw sugar on a given day.b.Find the probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day.c.How much raw sugar should be stocked for the plant each day so that the chance of running out of the raw sugar is only 0.05?

Answer: The mean (μ) of the plants is 4 tons. The probability density function of an exponential distribution is given by:

f(x)=\lambda e^{-\lambda x}\\But\ \lambda= 1/\mu=1/4 = 0.25\\Therefore:\\f(x)=0.25e^{-0.25x}\\

a) P(x > 5) = \int\limits^\infty_5 {f(x)} \, dx =\int\limits^\infty_5 {0.25e^{-0.25x}} \, dx =-e^{-0.25x}|^\infty_5=e^{-1.25}=0.2865

b) Probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day can be solved when considered as a binomial.

That is P(2 of the three plant use more than five tons) = C(3,2) × [P(x > 5)]² × (1-P(x > 5)) = 3(0.2865²)(1-0.2865) = 0.1757

c) Let b be the amount of raw sugar should be stocked for the plant each day.

P(x > a) = \int\limits^\infty_a {f(x)} \, dx =\int\limits^\infty_a {0.25e^{-0.25x}} \, dx =-e^{-0.25x}|^\infty_a=e^{-0.25a}

But P(x > a) = 0.05

Therefore:

e^{-0.25a}=0.05\\ln[e^{-0.25a}]=ln(0.05)\\-0.25a=-2.9957\\a=11.98

a  ≅ 12

6 0
2 years ago
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